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solmaris [256]
3 years ago
6

With what force will a car hit a tree if the car has a mass of 3,415 kg and it is accelerating at

Physics
1 answer:
weeeeeb [17]3 years ago
3 0

Answer:

F= 17,075\ N

Explanation:

When the car is under an accelerating force and hits a tree, the instant force received by the tree is the same force that is accelerating the car.

The accelerating force can be calculated using Newton's second law:

F=m\cdot a

Where m is the mass of the car and a is the acceleration.

F=3,415\ kg\cdot 5\ m/s^2

\boxed{F= 17,075\ N}

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If an object's mass increases, its--
aev [14]

Answer:

both kinetic and potential energy

Explanation:

this is your ans

I hope it helps mate

I will always help you understanding your assingments

have a great day

#Captainpower :)

8 0
3 years ago
With what speed must you approach a source of sound to observe a 25% change in frequency?
insens350 [35]
Sound source is at rest, you are moving with velocity v, f = frequency, c = speed of sound:

f = f0(1 + v/c)

115 = 100(1 + v/343)
115 = 100 + 100v/343
15 = 100v/343
v = 15*343/100
<span> v = 51,45 m/s </span>
5 0
3 years ago
3. A 142 g baseball is thrown at a speed of 42.9 m/s. What is the kinetic energy of the baseball at this moment?
krok68 [10]
Kinetic energy=1/2mv^2
=1/2(142*10^-3)(42.9)^2=130.6=131J
8 0
3 years ago
2 Points
Mademuasel [1]

According to Newton's Second Law of Motion :

The Force acting on an Object is equal to Product of Mass of the Object and Acceleration produced due to the Force.

:\implies  Force acting = Mass of the Object × Acceleration

Given : Force = 50 newton and Mass of the Object = 10 kg

Substituting the respective values in the Formula, we get :

:\implies  50 N = 10 kg × Acceleration

:\implies \mathsf{Acceleration = \dfrac{50\;N}{10\;kg}}

:\implies Acceleration of the Object = 5 m/s²

4 0
3 years ago
The Hubble Space Telescope in orbit above the Earth has a 2.4 m circular aperture. The telescope has equipment for detecting ult
strojnjashka [21]

Answer:

Option d

The minimum angular separation between two objects that the Hubble Space Telescope can resolve is 4.8x10^{-8}rad.  

Explanation:

The resulting image in a telescope that will be gotten from an object is a diffraction pattern instead of a perfect point (point spread function (PSF)).

That diffraction pattern is gotten because the light encounters different obstacles on its path inside the telescope (interacts with the walls and edges of the instrument).

 

The diffraction pattern is composed by a central disk, called Airy disk, and diffraction rings.    

 

The angular resolution is defined as the minimal separation at which two sources can be resolved one for another, or in other words, when the distance between the two diffraction pattern maxima is greater than the radius of the Airy disk.

The angular resolution can be determined in analytical way by means of the Rayleigh criterion.          

\theta = 1.22\frac{\lambda}{D}  (1)

Where \lambda is the wavelength and D is the diameter of the telescope.

Notice that it is necessary to express the wavelength in the same units than the diameter.

\lambda = 95nm \cdot \frac{1x10^{-9}m}{1nm} ⇒ 9.5x10^{-8}m

Finally, equation 1 can be used.

\theta = 1.22(\frac{9.5x10^{-8}m}{2.4m})

\theta = 4.8x10^{-8}rad              

Hence, the minimum angular separation between two objects that the Hubble Space Telescope can resolve is 4.8x10^{-8}rad.    

5 0
3 years ago
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