True because it is warmer closer to the equator
3Ba + N2 -----> Ba3N2
Ba is in the second group and metal, its charge = +2 in the compound.
N is non-metal, it is in 15th group, so it has 5 electrons on the last level, so it can take 3 electrons more(8-5=3). N has charge (-3) in compound.
Ba and N form compound Ba3N2.
Answer:
Add copper (II) oxide (insoluble base), a little at a time to the warm dilute sulfuric acid and stir until the copper (II) oxide is in excess (stops disappearing) Filter the mixture into an evaporating basin to remove the excess copper (II) oxide. Leave the filtrate in a warm place to dry and crystallize.