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xxMikexx [17]
4 years ago
6

Please help... What forms of energy are present in lighting a table lamp?​

Physics
2 answers:
prohojiy [21]4 years ago
6 0

Answer:

Electrical energy, Heat energy and Light energy.

Explanation:

Lighting a table lamp requires electricity and after being light up, light energy is produced and you will feel heat around it.

Wewaii [24]4 years ago
5 0
Electrical, Heat and Light energy are present in lighting a table lamp
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Two small stereo speakers are driven in step by the same variable-frequency oscillator. Their sound is picked up by a microphone
anygoal [31]

Answer:

The fundamental frequency at which the sound of speakers at the microphone produce constructive interference is 801.076458 Hz

Explanation:

For a given arrangement having constructive interference, we have;

R₁ - R₂ = 2·x = 0 + n·λ

The distance from one speaker to the microphone. R₁ = 4.50 m

The distance between the two speakers = 2.00 m

The angle formed between the direction from the microphone to the speaker closest and the directional path between the speakers = 90°

Therefore, by Pythagoras's theorem, the distance from the speaker furthest from the microphone, to the microphone, 'R₂' is given as follows;

R₂ = √(4.50² + 2.00²) = √(24.25) = 4.9244289009 ≈ 4.924

∴ R₂ ≈ 4.9244289 m

R₂ - R₁ = 4.9244289 m - 4.5 m = 0.4244289 m

For constructive interference, R₂ - R₁ =0.4244289 m = n·λ

For n = 1, we have;

R₂ - R₁ =0.4244289 m = n·λ = 1 × λ = λ

λ = 0.4244589 m

f = v/λ = 340 m/sec/(0.4244289 m) ≈ 801.076458 Hz

Therefore the lowest possible fundamental frequency at which the speakers produce constructive interference, f = 801.076458 Hz

7 0
3 years ago
A circular coil of wire of radius 5.0 cm has 20 turns and carries a current of 2.0 A. The coil lies in a magnetic field of magni
Korvikt [17]

Answer:a. Magnetic dipole moment is 0.3412Am²

b. Torque is zero(0)N.m

Explanation: The magnetic dipole moment U is given as the product of the number of turns n times the current I times the area A

That is,

U = n*I*A

But Area A is given as pi*radius² since it is a circular coil

Radius given is 5cm converting to meter we divide by 100 so we have our radius to be 0.05m. So area A is

A = 3.142*(0.05)² =7.86*EXP {-3} m²

Current I is 2 A

Number of turns is 20

So magnetic dipole moment U is

U = 20*2*7.86*EXP {-3}=0.3142A.m²

b. Torque is given as the cross product of the magnetic field B and magnetic dipole moment U

Torque = B x U =B*U*Sine(theta)

But since the magnetic field is directed parallel to the plane of the coil from the question, it means that the angle between them is zero and sine zero is equals 0(zero) if you substitute that into the formula for torque you will find out that your torque would equals zero(0)N.m

7 0
3 years ago
Emily sprains her ankle on her way home from school. Her mom suggests she use an “instant cold pack” to reduce the swelling. Whe
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4 0
3 years ago
A 240 kg motorcycle moves with a velocity of 8 m/s. What is its kinetic energy?
QveST [7]
1/2 x 240 x 64 = 120 X 64 = 7680 J
6 0
3 years ago
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saad has mass 80 kg when resting on the ground at the equator . what will be the centripetal acceleration on saad if the radius
Molodets [167]
Here,
         m=80 kg
         R= 6.4*10^6 m
       and t=24*3600=86400 s

Centripetal acceleration:
      a=ω²r
         =(2\pi /86400)^2 * 6.4*10^6
         =0.034 m/s²
6 0
3 years ago
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