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USPshnik [31]
2 years ago
9

saad has mass 80 kg when resting on the ground at the equator . what will be the centripetal acceleration on saad if the radius

of the earth R is 6.4×10^6 m.
Physics
1 answer:
Molodets [167]2 years ago
6 0
Here,
         m=80 kg
         R= 6.4*10^6 m
       and t=24*3600=86400 s

Centripetal acceleration:
      a=ω²r
         =(2\pi /86400)^2 * 6.4*10^6
         =0.034 m/s²
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3 years ago
Calculate the average drift speed of electrons traveling through a copper wire with a crosssectional area of 80 mm2 when carryin
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Answer:

The correct answer is 2.8*10^{-5}ms^{-1}

Explanation:

The formula for the electron drift speed is given as follows,

u=I/nAq

where n is the number of of electrons per unit m³, q is the charge on an electron and A is the cross-sectional area of the copper wire and I is the current. We see that we already have A , q and I. The only thing left to calculate is the electron density n that is the number of electrons per unit volume.

Using the information provided in the question we can see that the number of moles of copper atoms in a cm³ of volume of the conductor is 8.93/63.5 molcm^{-3}. Converting this number to m³ using very elementary unit conversion we get 140384molm^{-3}. If we multiply this number by the Avagardo number which is the number of atoms per mol of any gas , we get the number of atoms per m³ which in this case is equal to the number of electron per m³ because one electron per atom of copper contribute to the current. So we get,

n=140384*6.02*10^{23} = 8.45*10^{28}electrons.m^{-3}

if we convert the area from mm³ to m³ we get A=80*10^{-6}m^{2}.So now that we have n, we plug in all the values of A ,I ,q and n into the main equation to obtain,

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