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irinina [24]
3 years ago
5

Fernanda looked at a sample of paint under a microscope. At right is the sketch she made of what she saw. Label A points to the

solid particles of pigment that give the paint its color. The solid particles are the . Label B represents the liquid surrounding the solid particles. This liquid is called the for this mixture. This paint does not settle over time, so it is an example of a .
Chemistry
2 answers:
Degger [83]3 years ago
7 0

Answer:dispersed state

dispersed medium

colloid

ikadub [295]3 years ago
4 0

Answer:

Yes the scroll down or up? but she/he is correct honestly girl I hateee edgenuity rn

Explanation:

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What is it called when Earth’s magnetic poles change places?
Igoryamba

Answer:

Its b. Magnetic reversal

Explanation:

4 0
3 years ago
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An electrochemical cell is constructed such that on one side a pure lead electrode is in contact with a solution containing Pb2+
Ugo [173]

Answer:

-490.7 K

Explanation:

Given:

[Ni^2+]= 0.4 M

[Pb^2+]=0.002 M

∆V= -0.012 V

VNi= -0.250V

VPb= -0.126V

F= 96500 C

R= 8.314 JK-1 mol-1

n= 2

From

T= -nF/R [∆V-(VNi-VPb)/ln [Pb2+]/[Ni2+]]

T= 2(96500)/8.314[ (-0.012) -(-0.250) - (-0.126))/ln[0.002]/[0.4]

T= 23213.856(0.112/(-5.298))

T= -490.7 K

4 0
3 years ago
Each of the diagrams below shows an electrically neutral atom. fill in the missing number of protons (n) neutrons (and), electro
vova2212 [387]
What is the diagram?
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3 years ago
PLEASE!!! I NEED HELP ASAP!!
Lana71 [14]
W=m₁/m₀=2^(-t/T)

t=4.6·10⁹ years
T=5·10¹⁰ years

w=2^(-4.6·10⁹/5·10¹⁰)

w=0.9382
w=93.82%

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3 years ago
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In atmospheric chemistry, the following chemical reaction converts SO2, the predominant oxide of sulfur that comes from combusti
Misha Larkins [42]

Answer:

Explanation:

From the given information;

The chemical reaction can be well presented as follows:

\mathtt{SO_{2(g)} + \dfrac{1}{2}O_{2(g)} }  ⇄ \mathtt{3SO_{2(l)}}

Now, K is known to be the equilibrium constant and it can be represented in terms of each constituent activity:

i.e

K = \dfrac{a_{so_3}}{a_{so_2} a_{o_2}^{\frac{1}{2}}}

However, since we are dealing with liquids solutions;

K = \dfrac{1}{\dfrac{Pso_2}{P^0}\Big ( \dfrac{Po_2}{P^0} \Big)^{1/2}}   since the activity of a_{so_3} is equivalent to 1

Hence, under standard conditions(i.e at a pressure of 1 bar)

K = \dfrac{1}{Pso_2Po_2^{1/2}}

(b)

From the CRC Handbook, we are meant to determine the value of the Gibb free energy by applying the formula:

\Delta _{rxn} G^o = \sum \Delta_f \ G^o (products) - \sum \Delta_fG^o (reactants) \\ \\ = (1) (-368 \ kJ/mol) - (\dfrac{1}{2}) (0) - ((1) (-300.13 \ kJ/mol)) \\ \\ = -368 \ kJ/mol + 300.13 \ kJ/mol \\ \\  \simeq -68 \ kJ/mol

Thus, for this reaction; the Gibbs frree energy = -68 kJ/mol

(c)

Le's recall that:

At equilibrium, the instantaneous free energy is usually zero &

Q(reaction quotient) is equivalent to K(equilibrium constant)

So;

\mathtt{\Delta _{rxn} G = \Delta _{rxn} G^o + RT In Q}

\mathtt{0- \Delta _{rxn} G^o = RTIn K } \\ \\ \mathtt{ \Delta _{rxn} G^o = -RTIn K }  \\ \\  K = e^{\dfrac{\Delta_{rxn} G^o}{RT}} \\ \\  K = e^{^{\dfrac{67900 \ J/mol}{8.314 \ J/mol \times 298 \ K}} }

K =7.98390356\times 10^{11} \\ \\  \mathbf{K = 7.98 \times 10^{11}}

(d)

The direction by which the reaction will proceed can be determined if we can know the value of Q(reaction quotient).

This is because;

If  Q < K, then the reaction will proceed in the right direction towards the products.

However, if Q > K , then the reaction goes to the left direction. i.e to the reactants.

So;

Q= \dfrac{1}{Pso_2Po_2^{1/2}}

Since we are dealing with liquids;

Q= \dfrac{1}{1 \times 1^{1/2}}

Q = 1

Since Q < K; Then, the reaction proceeds in the right direction.

Hence, SO2 as well O2 will combine to yield SO3, then condensation will take place to form liquid.

8 0
3 years ago
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