Answer is: <span>the half-life of the radioisotope is 74 days.
</span>m₀ = 3.25 g.
m₁ = 1.21 g.
t = 105 d.
ln(m₀/m₁) = k· t.
ln(3.25/1.21) = k·105 d.
ln(2.685) = 105·k.
0.98 = 105k.
k = 0.0094.
t1/2 = ln2 / k.
t1/2 = 0.693 / 0.0094.
t1/2 = 73.72 days.
Answer:
Explanation:
A chemical bond is a lasting attraction between atoms, ions molecules that enables the formation of chemical compound.
Answer:
1M
Explanation:
First, let us write a balanced equation for the reaction. This is illustrated below:
NaOH + HCl —> NaCl + H2O
From the equation above,
nA (mole of acid) = 1
nB (mole of the base) = 1
Data obtained from the question include:
Vb (volume of base) = 50mL
Mb (Molarity of base) = 0.2M
Va (volume of acid) = 10mL
Ma (Molarity of acid) =?
Using MaVa/MbVb = nA/nB, we can calculate the molarity of the acid as follow:
Ma x 10/0.2 x 50 = 1
Cross multiply to express in linear form
Ma x 10 = 0.2 x 50
Divide both side by 10
Ma = (0.2 x 50)/10
Ma = 1M
The molarity of the acid is 1M
Answer:
0.5mol
Explanation
Please mark answer as brainliest
You are given both the energy level, n = 4, and the subshell, l = 3 on which the electrons reside.
The subshell is given to you by the angular momentum quantum number, l which can take value that ranges from 0 to n − 1
l = 0 → the s-subshell
l = 1 → the p-subshell
l = 2 → the d-subshell
l = 3 → the f-subshell
<u>For n = 4 and l = 3, ml can be -3, -2, -1, 0, +2, +2, and +3. </u>
<u>Each of these can have 2 electrons (+1/2 and -1/2 spin) for a total of 14 electrons.</u>
