Answer:
1.2 × 10⁴ cal
Explanation:
Given data
- Initial temperature: 80 °C
We can calculate the heat released by the water (
) when it cools using the following expression.

where
c is the specific heat capacity of water (1 cal/g.°C)

According to the law of conservation of energy, the sum of the heat released by the water (
) and the heat absorbed by the reaction (
) is zero.

A. 0.12 (mol/L)/s
rate = 1 x 10-2 • 2^2 • 3
Answer: 4
Explanation:
4 is the only one that has to products as well as having the plus at the bottom
Answer: CaSO3
Explanation:Please see attachment for explanation