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FinnZ [79.3K]
3 years ago
12

Chili can be made using ground meat or chunks of meat Which would you choose if you were in a hurry? Explain.

Chemistry
2 answers:
morpeh [17]3 years ago
7 0
I wouldchoose ground meet because it woukd cook much faster
goblinko [34]3 years ago
6 0
I would choose Ground meat if i was in a hurry Hope this helps:)
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Describe the motion of a pendulum in terms of kinetic and potential energy. As the pendulum moves from its greatest to lowest he
Bezzdna [24]
Highest height : Potential energy = high | Kinetic energy = low

Lower height: kinetic Potential energy = low | Kinetic energy = high

*Remember it by when its higher thats when it has "high potential" :)*
6 0
3 years ago
A river with a flow of 50 m3/s discharges into a lake with a volume of 15,000,000 m3. The river has a background pollutant conce
spin [16.1K]

Explanation:

The given data is as follows.

       Volume of lake = 15 \times 10^{6} m^{3} = 15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}

        Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = 5.6 \times 15 \times 10^{9} mg

                                                                    = 84 \times 10^{9} mg

                                                                    = 84 \times 10^{3} kg

Flow rate of river is 50 m^{3} sec^{-1}

Volume of water in 1 day = 50 \times 10^{3} \times 86400 liter

                                          = 432 \times 10^{7} liter

Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are 2.9792 \times 10^{10} mg or 2.9792 \times 10^{4} kg

Flow rate of sewage = 0.7 m^{3} sec^{-1}

Volume of sewage water in 1 day = 6048 \times 10^{4} liter

Concentration of sewage = 300 mg/L

Total amount of pollutants = 1.8144 \times 10^{10} mg or 1.8144 \times 10^{4}kg

Therefore, total concentration of lake after 1 day = \frac{131936 \times 10^{6}}{1.938 \times 10^{10}}mg/ l

                                        = 6.8078 mg/l

                 k_{D} = 0.2 per day

       L_{o} = 6.8078

Hence, L_{liquid} = L_{o}(1 - e^{-k_{D}t}

             L_{liquid} = 6.8078 (1 - e^{-0.2 \times 1})  

                             = 1.234 mg/l

Hence, the remaining concentration = (6.8078 - 1.234) mg/l

                                                             = 5.6 mg/l

Thus, we can conclude that concentration leaving the lake one day after the pollutant is added is 5.6 mg/l.

5 0
3 years ago
Would gallium, atomic #31, likely form a action or an anion?
Stolb23 [73]
Assuming you meant cation and not action, gallium would most likely form a cation because it is a group A element
4 0
3 years ago
5.82 760.<br> Х<br> 425.976<br> answer should have<br> sig.figs.<br> calculated answer:
Mekhanik [1.2K]

Answer:

2482.4177376

Explanation:

1: 5.82 760  times   425.976

2: You will find the answer that is 2482.4177376

<em><u>Hope this helps.</u></em>

7 0
3 years ago
What will the outcome of putting litumus paper into distilled water
Kay [80]
If it is blue litmus paper, it will remain blue. If it is red litmus paper, it will remain red. Water is neither an acid nor a base so it will not change the litmus paper.
5 0
3 years ago
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