However, some common household products, including drain and toilet bowl cleaners and some dishwasher detergents, contain damaging caustic substances, such as sodium hydroxide and sulfuric acid. Caustic substances (strong acids and alkalis), when swallowed, can burn the tongue, mouth, esophagus, and stomach.
Answer:
0.208mole of CO2
Explanation:
First, let us calculate the number of mole of HC3H3O2 present.
Molarity of HC3H3O2 = 0.833 mol/L
Volume = 25 mL = 25/100 = 0.25L
Mole =?
Mole = Molarity x Volume
Mole = 0.833 x 0.25
Mole of HC3H3O2 = 0.208mole
Now, we can easily find the number of mole of CO2 produce by doing the following:
NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2
From the equation,
1mole of HC2H3O2 produced 1 mole of CO2.
Therefore, 0.208mole of HC2H3O2 will also produce 0.208mole of CO2
The question is incomplete, the complete question is;
Groups of the periodic table correspond to elements with a. the same color b. the same atomic number c. similar chemical properties d. similar numbers of neutrons
Answer:
similar chemical properties
Explanation:
In the periodic classification of elements, elements are divided into groups and periods. Elements in the same group of the periodic table have the same number of outermost electrons and share very similar chemical properties.
Elements in the same period have the same number of shells and the same maximum energy level of the outermost electron. Chemical properties carry markedly across a period.
Answer:
If you are creating the reaction, then you would agitate the particles to cause them to become more active.
Explanation:
This can be done by stirring them, heating them up, or by swirling the container.
Hello!
Three nails have a mass of 3.05 g. How many moles of iron do they contain?
Data:
3 nails of iron = 3.05 g (by nail)
The atomic mass of iron is 55.845 amu, so the molar mass is:
M = 55.845 → M ≈ 56 g / mol
With a simple 3 rule:
56 g → 1 mol
3.05 g → y mol
Therefore:





Soon:
3 nails → 3*0.05446 = 0.1638 moles (answer)
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I Hope this helps, greetings ... Dexteright02! =)