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4 years ago

Conservation methods are needed worldwide for many reasons. All but one is a reason to support conservation

Physics

2 answers:

Flura [38]4 years ago

8 0

The answer is undiscovered lands will provide plenty of natural resources.

Zigmanuir [339]4 years ago

5 0

D. undiscovered lands will provide plenty of natural resources
I just answered this on usatest prep and this is the answer

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Two cylinders A and B at the same temperature contain the same quantity of the same kind of gas. Cylinder A has three times the

astraxan [27]

Answer:

so pressure in A must be one third the pressure in B

Explanation:

We shall apply gas law to the cylinders A and B . Since their quantity are same so their no of mole will also be same .

For cylinder A

Temperature T , volume 3V , pressure P₁ , no of mole = n

P₁ X 3V = n R T

For cylinder B

Temperature T , volume V , pressure P₂ ,no of mole = n

P₂ X V = n R T

From the two equation above

P₁ X 3V = P₂ X V

$\frac{P_1}{P_2}=\frac{1}{3}$

P₁ = P₂ / 3

so pressure in A must be one third the pressure in B

3 0

3 years ago

A track is traveling a. a speed of 25.0 m/s along a level road. A crate is resting on the bed of the truck, and the coefficient

Mice21 [21]

To solve this problem it is necessary to apply the concepts related to

conservation of energy, for this case manifested through work and kinetic energy.

$W = \Delta KE$

$W = F*d$

Where,

F= Force (Frictional at this case $F_r = \mu N$ )

d= Distance

$\Delta KE = \frac{1}{2} mv^2$

Where,

m = mass

v = velocity

Equation both terms,

$F*d = \frac{1}{2}mv^2$

$\mu mg *d = \frac{1}{2}mv^2$

$\mu g * d = \frac{1}{2}v^2$

$d = \frac{1}{2} \frac{v^2}{\mu g}$

Replacing with our values we have that

$d = \frac{1}{2} \frac{25^2}{0.65*9.8}$

$d = 49.05m$

Therefore the shortest distance in which the truck can come to a halt without causing the crate to slip forward relative to the truck is 49.05m

6 0

3 years ago

Can someone help me solve number 3 for chemical equations?

Monica [59]

Answer:

I'm pretty sure it should be 4KClO3-->3KClO4+1KCl

Explanation:

3 0

3 years ago

an instrument used a battery that provides 500 j of energy for 1200 seconds. what is the power of the instrument?

matrenka [14]

Answer: 0.42watts

Explanation:

Energy of the battery = 500 J

Time = 1200 seconds

Power of the instrument = ?

Recall that power is the rate of energy expended in doing work. Thus, power is energy expended divided by time taken.

i.e Power = (energy/time)

Power = 500J/1200 seconds

Power = 0.416 watts (Round to the nearest hundredth which is 0.42 watts)

Thus, the power of the instrument is 0.42watts

5 0

4 years ago

How much work does a bricklayer do to carry 30.2 kg of bricks from the ground up to the third floor (height = 11.1 m) of a build

Julli [10]

Answer:

Work done by the bricklayer, W = 3.285 kJ

Therefore, the gravitational potential energy of the brick-Earth system = 3.285 kJ

Explanation:

Work done is the product of applied force and distance moved by the force.

The force on an object in the gravitational field is equal to the product of the mass of the object and acceleration due to gravity This force is the weight of the object or body. In lifting an object from a lower height to a higher one, the distance moved is equal to the increase in height.

Work done in lifting an object in a gravitational field = mgh

where m = mass of the object, g = acceleration due to gravity, h = height

From the question, m = 30.2 kg, g = 9.8 m/s², h = 11.1 m

Work done by the bricklayer = 30.2 * 9.8 * 11.1 = 3285.156 J

Work done by the bricklayer, W = 3.285 kJ

Gravitational Potential Energy, PEg = mgh = W

Therefore, the gravitational potential energy of the brick-Earth system = 3.285 kJ

7 0

3 years ago