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Alecsey [184]
3 years ago
11

Two cylinders A and B at the same temperature contain the same quantity of the same kind of gas. Cylinder A has three times the

volume of cylinder B. What can you conclude about the pressures the gases exert? Show all workings. [15 marks] a. b. c. d. The density of gas in A and B are the same. The pressure in A is three times the pressure in B. The pressures in A and B must be equal. The pressure in A must be one-third the pressure in B.
Physics
1 answer:
astraxan [27]3 years ago
3 0

Answer:

so pressure in A must be one third the pressure in B

Explanation:

We shall apply gas law to the cylinders A and B . Since their quantity are same so their no of  mole will also be same .

For cylinder A

Temperature T , volume 3V , pressure  P₁ , no of mole = n

so

P₁ X 3V = n R T

For cylinder B

Temperature T , volume V , pressure  P₂ ,no of  mole = n

so

P₂ X V = n R T

From the two equation above

P₁ X 3V = P₂ X V

\frac{P_1}{P_2}=\frac{1}{3}

P₁ = P₂ / 3

so pressure in A must be one third the pressure in B

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A projectile fired from a gun has initial horizontal and vertical components of velocity equal to 60 m/s and 80 m/s, respectivel
DerKrebs [107]

This question involves the concepts of projectile motion and launch speed.

(a) The initial launch speed of the projectile is "100 m/s".

(b) The launch angle of the projectile is "53.13°".

<h3>(a) LAUNCH SPEED</h3>

A projectile motion is a motion that takes place on both x and y axes, simultaneously. In this motion the initial launch speed is given by the following formula:

v_o=\sqrt{v_{ox}^2+v_{oy}^2}

where,

  • v_o = initial launch speed = ?
  • v_{ox} = horizontal component of initial launch speed = 60 m/s
  • v_{oy} = vertical component of initial launch speed = 80 m/s

Therefore,

v_o = \sqrt{(60\ m/s)^2+(80\ m/s)^2}\\\\v_o = 100 m/s

<h3>(b) LAUNCH ANGLE</h3>

Launch angle is given by th following formula:

\theta = tan^{-1}(\frac{v_{oy}}{v_{ox}})=tan^{-1}(\frac{80\ m/s}{60\ m/s})\\\\\theta=53.13^o

Learn more about the projectile motion here:

brainly.com/question/11049671

6 0
3 years ago
Rhea kicks a soccer ball at 13km/h to Sean after kicking the ball the speed of the soccer ball from Rhea reference frame is 13km
Zinaida [17]

Answer:

Sean is standing still, and Rhea is running toward Sean while kicking the ball.

<em>Note: The question is in complete. The complete question is given below:</em>

<em>Rhea kicks a soccer ball at 13 km/h to Sean. After kicking the ball, the speed of the soccer ball from Rhea's reference frame is 13 km/h. The speed of the soccer ball from Sean's reference frame is 22 km/h.  Which conclusion is best supported by the information? </em>

<em>Sean is standing still, and Rhea is running toward Sean while kicking the ball.</em>

<em>Rhea is standing still after kicking the ball, and Sean is running away from Rhea.</em>

<em>Both soccer players are standing still after the ball is kicked.</em>

<em>Both soccer players are running while the ball is in motion.</em>

Explanation:

A reference frame is a position from which something is observed.

Since from the reference frame of Rhea, the ball is moving at a speed of 13 km/h after he kicks the ball at a speed of 13km/h whereas from the frame of reference of Sean, the ball is moving at a speed of 22km/h, there is a difference in the speed of the ball as seen from Rhea's and Sean's frame of reference of about 9 km/h. This difference can only be due to relative motion between the ball and Rhea.

Therefore, the best conclusion supported by the given information is that Sean is standing still, and Rhea is running toward Sean while kicking the ball.

4 0
3 years ago
A soccer ball is kicked with a speed of 22m/s at an angle of 35.0º above the horizontal. If the ball lands at the same level fro
Lisa [10]

Answer:

2.57 seconds

Explanation:

The motion of the ball on the two axis is;

x(t) = Vo Cos θt

y(t) = h + Vo sin θt - 1/2gt²

Where; h is the initial height from which the ball was thrown.

Vo is the initial speed of the ball, 22 m/s , θ is the angle, 35° and g is the gravitational acceleration, 9.81 m/s²

We want to find the time t at which y(t) = h

Therefore;

y(t) = h + Vo sin θt - 1/2gt²

Whose solutions are, t = 0, at the beginning of the motion, and

t = 2 Vo sinθ/g

  = (2 × 22 × sin 35°)/9.81

  = 2.57 seconds

6 0
3 years ago
Does the size of the magnetic field change with the size of the magnet?
mestny [16]

Answer:

Not all of the time, it can also depend on the strength of the magnet.

Explanation:

say you have a small very strong magnet, that might work just as well as a large but week magnet.

4 0
3 years ago
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IRISSAK [1]

Answer:

I would use a propeller like the first or second just from my experience. Just play around with the different ones and see which one works best for you.Don't make the propeller too thick or thin or else it may not work.

Explanation:

Have a great day! Good luck!

4 0
3 years ago
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