1 mols of Aluminium ion forms 1 mol aluminium phosphate
Molar mass of AlPO_4
Moles of AlPO_4
- 61µg/106
- 0.000061/106
- 5.75×10^{-7}
- 57.5µmol
Moles of Al3+=57.5µmol
Networks of feeding relationships is correct
Answer:
the answer has been given below have a good day
Explanation:
mark as brainiest
Answer:
D. length × width
Explanation:
eg. 30 cm(length) × 20cm(width) = 600cm²
Answer:
1 : 2
Explanation:
From the question given, we obtained the following information:
T1 = 287°C = 287 +273 = 560K
T1 = 587°C = 587 +273 =860K
V1 = V
V2 =?
V1 /T1 = V2 /T2
V/560 = V2/860
Cross multiply
V2 x 560 = 860 x V
Divide both side by 560
V2 = (860 x V) / 560
V2 = 1.54V = 2V
The ratio of initial to final volume =
V1 : V2
= V : 2V
= 1 : 2
