Difference between acids and bases in terms of ions
2 answers:
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Answer:
(a)
(b)
(c)
(d)
Explanation:
Hello,
In this case, we define the pH in terms of the concentration of hydronium ions as:
Which is directly computed for the strong hydrochloric acid (consider a complete dissociation which means the concentration of hydronium equals the concentration of acid) in (a) and (c) as shown below:
(a)
(b)
Nevertheless, for the strong sodium hydroxide, we don't directly compute the pH but the pOH since the concentration of base equals the concentration hydroxyl in the solution:
Thus, we have:
(b)
(d)
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Answer:
see explaination
Explanation:
We are given the (R)-3-bromo-2,3-dimethylpentane and asking to draw the curved arrow which is the showing the mechanism for first-order substitution and first-order elimination reactions. We know the formation of carbocation is the rate determining step in the first-order substitution and first-order elimination reactions.
So in the (R)-3-bromo-2,3-dimethylpentane there is –Br gets removed and formed the tertiary carbocation which is more stable, so the curved arrows in Box 1 to depict the flow of electrons and intermediate in Box 2.
Check attachment
Explanation:
where,
R = Gas constant =
T = temperature =
= equilibrium constant at 600°C = 0.900
Putting values in above equation, we get:
The ΔG° of the reaction at 764.85 J/mol is 764.85 J/mol.
Equilibrium constant at 600°C =
Equilibrium constant at 1000°C =
The ΔH° of the reaction at 600 C is -18,969.30 J/mol.
ΔG° = ΔH° - TΔS°
764.85 J/mol = -18,969.30 J/mol - 873.15 K × ΔS°
ΔS° = -22.60 J/K mol
The ΔS° of the reaction at 600 C is -22.60 J/K mol.
Partial pressure of carbon dioxide =
Partial pressure of carbon monoxide =
Where mole fraction of carbon dioxide and carbon monoxide gas.
The expression of is given by:
Mole fraction of carbon dioxide at 600°C is 0.474.