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2 years ago

Difference between acids and bases in terms of ions

Chemistry

2 answers:

Lady_Fox [76]2 years ago

8 0

Answer:

The answer will be listed below.

Explanation:

An acid is a substance that produces (H+) as the only positive ion when mixed with water. A base is a substance that produces (OH–) as the only negative ion when mixed with water.

dalvyx [7]2 years ago

4 0

Answer:

An acid increases the concentration, A base is a substance that releases hydroxide

Explanation: A base donates electrons and accepts protons, and acid is a substance that donates protons.

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A chemist titrates 160.0mL of a 0.3403M aniline C6H5NH2 solution with 0.0501M HNO3 solution at 25°C . Calculate the pH at equiva

maxonik [38]

Answer : The pH of the solution is, 5.24

Explanation :

First we have to calculate the volume of $HNO_3$

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the initial molarity and volume of $C_6H_5NH_2$ .

$M_2\text{ and }V_2$ are the final molarity and volume of $HNO_3$ .

We are given:

$M_1=0.3403M\\V_1=160.0mL\\M_2=0.0501M\\V_2=?$

Putting values in above equation, we get:

$0.3403M\times 160.0mL=0.0501M\times V_2\\\\V_2=1086.79mL$

Now we have to calculate the total volume of solution.

Total volume of solution = Volume of $C_6H_5NH_2$ + Volume of $HNO_3$

Total volume of solution = 160.0 mL + 1086.79 mL

Total volume of solution = 1246.79 mL

Now we have to calculate the Concentration of salt.

$\text{Concentration of salt}=\frac{0.3403M}{1246.79mL}\times 160.0mL=0.0437M$

Now we have to calculate the pH of the solution.

At equivalence point,

$pOH=\frac{1}{2}[pK_w+pK_b+\log C]$

$pOH=\frac{1}{2}[14+4.87+\log (0.0437)]$

$pOH=8.76$

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-8.76\\\\pH=5.24$

Thus, the pH of the solution is, 5.24

4 0

3 years ago

Please help!!! ASAP

bekas [8.4K]

Na 2Co3

1*23=23. 2*12=24. 6*16=96

23+24+96=143

(23*100)/143. (24*100)/143. (96*100)/143

=16%. =16.7%. =67.1%

5 0

2 years ago

It takes 338. kJ/mom to break a carbon-chlorine single bond. Calculate the maximum wavelength of light for which a carbon-chlori

Vesnalui [34]

Answer: The maximum wavelength of light for which a carbon-chlorine Single bond could be broken by absorbing a single photon is 354 nm

Explanation:

The relation between energy and wavelength of light is given by Planck's equation, which is:

$E=\frac{Nhc}{\lambda}$

where,

E = energy of the light = $338kJ=338000J$ (1kJ=1000J)

N= avogadro's number

h = Planck's constant

c = speed of light

$\lambda$ = wavelength of light

$338\times 1000J=\frac{6.023\times 10^{23}\times 6.6\times 10^{-34}\times 3\times 10^{8}}{\lambda}$

${\lambda}=0.354\times 10^{-6}m=354nm$ $(1nm=10^{-9}m$

Thus the maximum wavelength is 354 nm

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3 years ago

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lina2011 [118]

For the very last question you would first divide 8,900 by 12 and the number you get will be the answer. You should get 741.66

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Anika [276]

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