Answer: 10L
Explanation:
Given that:
Initial pressure P1 = 1 atm
New pressure P2 = 3 atm
Initial volume V2 = 30 L
New volume V2 = ?
Since pressure and volume are involved, apply the formula for Boyle's law
P1V1 = P2V2
1 atm x 30L = 3 atm x V2
30 atm L = 3 atm x V2
V2 = (30 atm L / 3 atm)
V2 = 10L
Thus, volume changed to 10 liters
Answer:Videos
For example, when oxygen and hydrogen react to produce water, one mole of oxygen ... These conversion factors state the ratio of reactants that react but do not tell ... In a typical chemical equation, an arrow separates the reactants on the left ... For example, to determine the number of mol
Answer:
Option D: More than 30 seconds
Explanation:
The enzyme CATALASE is found in almost all living organisms. CATALASE helps in the decomposition of one substance into another substance. CATALASE will breaks down hydrogen peroxide into water and oxygen.
When the potatoes were boiled it will surely produce no bubbles because the heat would have degrade the enzyme - catalase While the potatoes at room temperature potato produced the most bubbles because catalase works best at a room temperature.
If the potato solution was boiled for 10 minutes and cooled for 10 minutes before being tested, the average time for the disks to float to the surface of the hydrogen peroxide solution would be MORE THAN 30 SECONDS
Answer: , 4 molecules of ammonia, NH3(g) is produced; 2 molecules of ammonia, NH3(g) is produced respectively
Explanation:
The balanced equation is stated below N2(g) + 3H2(g) → 2NH3(g)
1 mole of N2(g) reacts with 3 moles of H2(g) to yield 2 moles of NH3(g)
1) If 2 molecules of N2 react, then the balanced equation will be
2N2(g) + 6H2(g) → 4NH3(g)
Thus, 4 molecules of ammonia, NH3(g) is produced
2) If 3 molecules of H2 react, then the balanced equation will be
N2(g) + 3H2(g) → 2NH3(g)
Thus, 2 molecules of ammonia, NH3(g) is produced
Answer: The reaction is first order overall.
Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
![Rate=k[A]^x[B]^y](https://tex.z-dn.net/?f=Rate%3Dk%5BA%5D%5Ex%5BB%5D%5Ey)
k= rate constant
For the given rate law:
![Rate=k[A]^1[B]^1](https://tex.z-dn.net/?f=Rate%3Dk%5BA%5D%5E1%5BB%5D%5E1)
x = 1= order with respect to A
y =1= order with respect to B
n =( x+y)= (1+1) = 2 = Total order
a) If [A] is doubled, the reaction rate will increase by a factor of 2: True
![Rate'=k[2A]^1[B]^1](https://tex.z-dn.net/?f=Rate%27%3Dk%5B2A%5D%5E1%5BB%5D%5E1)
![Rate'=k[2]^1[A]^1[B]^1](https://tex.z-dn.net/?f=Rate%27%3Dk%5B2%5D%5E1%5BA%5D%5E1%5BB%5D%5E1)
![Rate'=[2]^1\times Rate](https://tex.z-dn.net/?f=Rate%27%3D%5B2%5D%5E1%5Ctimes%20Rate)
![Rate'=[2]\times Rate](https://tex.z-dn.net/?f=Rate%27%3D%5B2%5D%5Ctimes%20Rate)
b) The reaction is first order overall: False
The overall order is 1+1= 2.
c) k is the reaction rate constant: True
k= rate constant
d) The reaction is first order in [B]: True
For the given rate law:
x = 1= order with respect to A
e) The reaction is first order in [A]: True
For the given rate law:
y =1= order with respect to B
