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Anna35 [415]
3 years ago
9

1000 cm3 of hydrogen gas (hydrogen molecules, H2) contains x number of molecules at room temperature and pressure. Determine the

number of atoms in 500 cm3 of radon gas (radon atoms) at the same temperature and pressure
Chemistry
1 answer:
Gekata [30.6K]3 years ago
7 0

Answer: Number of atoms in 500cm^3 of radon gas (radon atoms) at the same temperature and pressure is \frac{x}{2}

Explanation:

According to avogadro's law, volume of a gas is directly proportional to the number of moles present when temperature and pressure is constant.:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

V_1 = Volume of the hydrogen gas = 1000cm^3

n_1 =  moles of hydrogen gas = \frac{xmolecules}{6.023\times 10^{23}molecules}

V_2=  Volume of the radon gas =500cm^3

n_1 =  moles of radon gas = ?

\frac{1000}{\frac{x}{6.023\times 10^{23}}}=\frac{500}{\frac{y}{6.023\times 10^{23}}}

y=\frac{x}{2}

Thus the number of atoms in 500cm^3 of radon gas (radon atoms) at the same temperature and pressure is \frac{x}{2}

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             %age Yield  =  51.45 %

Solution:

Step 1: Convert Kg into g

68.5 Kg CO  =  68500 g CO

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Step 2: Find out Limiting reactant;

The Balance Chemical Equation is as follow;

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According to Equation,

                   28 g (1 mol) CO reacts with  =  4 g (2 mol) of H₂

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Solving for X,

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Step 3: Calculate Theoretical Yield

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            4 g (2 mol) H₂ reacts to produce  =  32 g (1 mol) Methanol

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                          8600 g H₂ will produce  =  X g of CH₃OH

Solving for X,

                    X  =  (8600 g × 32 g) ÷ 4 g

                     X =  68800 g of CH₃OH

Step 4: Calculate %age Yield

                     %age Yield  =  Actual Yield ÷ Theoretical Yield × 100

Putting Values,

                     %age Yield  =  3.54 × 10⁴ g ÷ 68800 g × 100

                     %age Yield  =  51.45 %


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