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Anna35 [415]
3 years ago
9

1000 cm3 of hydrogen gas (hydrogen molecules, H2) contains x number of molecules at room temperature and pressure. Determine the

number of atoms in 500 cm3 of radon gas (radon atoms) at the same temperature and pressure
Chemistry
1 answer:
Gekata [30.6K]3 years ago
7 0

Answer: Number of atoms in 500cm^3 of radon gas (radon atoms) at the same temperature and pressure is \frac{x}{2}

Explanation:

According to avogadro's law, volume of a gas is directly proportional to the number of moles present when temperature and pressure is constant.:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

V_1 = Volume of the hydrogen gas = 1000cm^3

n_1 =  moles of hydrogen gas = \frac{xmolecules}{6.023\times 10^{23}molecules}

V_2=  Volume of the radon gas =500cm^3

n_1 =  moles of radon gas = ?

\frac{1000}{\frac{x}{6.023\times 10^{23}}}=\frac{500}{\frac{y}{6.023\times 10^{23}}}

y=\frac{x}{2}

Thus the number of atoms in 500cm^3 of radon gas (radon atoms) at the same temperature and pressure is \frac{x}{2}

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Juliette [100K]

Answer:

D) 2s^12p^3

Explanation:

Carbon.

The electronic configuration is -  

1s^22s^22p^2

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, Carbon has 2 singly occupied orbitals.

But in methane, CH_4 it forms 4 bonds. So, 1 electron each from 2s orbital jumps to the next orbital in the p subshell.

Thus, the configuration is:-

1s^22s^22p^2

Thus, the valence electron configuration is:-

2s^12p^3

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Carbon dioxide is produced by the human body through
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Answer:

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What two methods are used for determining the age of rocks and fossils?
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first one because absolute dating is a thing for rock layers

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Glacier National Park in Montana is approximately 4,100 ft above sea level with an atmospheric pressure of 681 torr. At what tem
lapo4ka [179]

Answer : The temperature of liquid is, 369.9 K

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of liquid at 373 K = 681 torr

P_2 = vapor pressure of liquid at normal boiling point = 760 torr

T_1 = temperature of liquid = ?

T_2 = normal boiling point of liquid = 373 K

\Delta H_{vap} = heat of vaporization = 40.7 kJ/mole = 40700 J/mole

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Now put all the given values in the above formula, we get:

\ln (\frac{760torr}{681torr})=\frac{40700J/mole}{8.314J/K.mole}\times (\frac{1}{T_1}-\frac{1}{373K})

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6 0
3 years ago
Read 2 more answers
g Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.71 g of ethane i
Kamila [148]

Answer:

6.05g

Explanation:

The reaction is given as;

Ethane + oxygen --> Carbon dioxide + water

2C2H6 + 7O2 --> 4CO2 + 6H2O

From the reaction above;

2 mol of ethane reacts with 7 mol of oxygen.

To proceed, we have to obtain the limiting reagent,

2,71g of ethane;

Number of moles = Mass / molar mass = 2.71 / 30 = 0.0903 mol

3.8g of oxygen;

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If 0.0903 moles of ethane was used, it would require;

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0.0903 = x

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This means that oxygen is our limiting reagent.

From the reaction,

7 mol of oxygen yields 4 mol of carbon dioxide

0.2375 yields x?

7 = 4

0.2375 = x

x = 0.1357

Mass = Number of moles * Molar mass = 0.1357 * 44 = 6.05g

8 0
3 years ago
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