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3 years ago

What will happen if pressure is increased?

2 answers:

8 0

When there is an increase in pressure, the equilibrium will shift towards the side of the reaction with fewer moles of gas. When there is a decrease in pressure, the equilibrium will shift towards the side of the reaction with more moles of gas.

melomori [17]3 years ago

8 0

Increase the pressure on what ?

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At 35°C, Kc = 1.6 multiplied by10-5 for the following reaction

Brums [2.3K]

Answer : The equilibrium concentrations of all species $NO,Cl_2\text{ and }NOCl$ are, 0.05 M, 0.043 M and 0.975 M respectively.

Explanation : Given,

Moles of $NO$ = 2 mole

Moles of $Cl_2$ = 1 mole

Volume of solution = 1 L

Initial concentration of $NO$ = 2 M

Initial concentration of $Cl_2$ = 1 M

The given balanced equilibrium reaction is,

$2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)$

Initial conc. 2 M 1 M 0

At eqm. conc. (2-2x) M (1-x) M (2x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[NOCl]^2}{[NO]^2[Cl_2]}$

The $K_c$ for reverse reaction = $\frac{1}{1.6\times 10^{-5}}$

Now put all the given values in this expression, we get :

$\frac{1}{1.6\times 10^{-5}}=\frac{(2x)^2}{(2-2x)^2\times (1-x)}$

By solving the term 'x', we get :

x = 0.975

Thus, the concentrations of $NO,Cl_2\text{ and }NOCl$ at equilibrium are :

Concentration of $NO$ = (2-2x) M = (2 - 2 × 0.975) M = 0.05 M

Concentration of $Cl_2$ = (1-x) M = 1 - 0.975 = 0.043 M

Concentration of $NOCl$ = x M = 0.975 M

Therefore, the equilibrium concentrations of all species $NO,Cl_2\text{ and }NOCl$ are, 0.05 M, 0.043 M and 0.975 M respectively.

6 0

3 years ago

A 0.1014 g sample of a purified compound containing C, H, and, O was burned in a combustion apparatus and produced 0.1486 g CO2

Alina [70]

Answer: The empirical formula for the given compound is $CH_2O$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=0.1486g$

Mass of $H_2O=0.0609g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.1486 g of carbon dioxide, $\frac{12}{44}\times 0.1486=0.0405g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0609 g of water, $\frac{2}{18}\times 0.0609=0.00677$ of hydrogen will be contained.

Mass of oxygen in the compound = (0.1014) - (0.0405 + 0.00677) = 0.054 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.0405g}{12g/mole}=0.003375moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.00677g}{1g/mole}=0.00677moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.054g}{16g/mole}=0.003375moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.485 moles.

For Carbon = $\frac{0.003375}{0.003375}=1$

For Hydrogen = $\frac{0.00677}{0.003375}=2.00\times 2$

For Oxygen = $\frac{0.003375}{0.003375}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 2 : 1

The empirical formula for the given compound is $C_1H_2O_1=CH_2O$

Thus, the empirical formula for the given compound is $CH_2O$

8 0

3 years ago

What can you infer if the fossil of a marine organism is found in an area that is now dry land?

Deffense [45]

Answer:

Fossils also help us to infer why dinosaurs and other organisms became extinct. Fossils tell us that there was a mass extinction at the time of the dinosaurs. They died out about 65 million years ago, along with more than half of all the other animal and plant species. ... Without plants, dinosaurs could not survive.

Explanation:

hope it will help you have a great day bye and Mark brainlist if the answer is correct

$kai6417$

#carry on learning

4 0

2 years ago

What is the tendency of a solute to change the boiling point of a solid called?

Bumek [7]

Boiling point elevation

6 0

4 years ago

Read 2 more answers

Fish breathe the dissolved air in water through their gills. Assuming the partial pressures of oxygen and nitrogen in air to be

amid [387]

Answer:

X(O₂) = 0.323

X(N₂) = 0.677

Explanation:

We have the partial pressures of oxygen (O₂) and nitrogen (N₂):

P(O₂) = 0.20 atm

P(N₂) = 0.80 atm

In order to solve the problem, you need the solubilities of each gas in water at 298 K. We can consider 1.3 x 10⁻³ mol/(L atm) for oxygen (O₂) and 6.8 x 10⁻⁴mol/(L atm) for nitrogen (N₂) from the bibliography.

s(O₂) = 1.3 x 10⁻³ mol/(L atm)

s(N₂) = 6.8 x 10⁻⁴mol/(L atm)

So, we calculate the concentration (C) of each gas as the product of its partial pressure (P) and the solubility (s):

C(O₂) = P(O₂) x s(O₂) = 0.20 atm x 1.3 x 10⁻³ mol/(L atm) = 2.6 x 10⁻⁴mol/L

C(N₂) = P(N₂) x s(N₂) = 0.80 atm x 6.8 x 10⁻⁴mol/(L atm) = 5.44 x 10⁻⁴ mol/L

In 1 liter of water, we have the following number of moles (n):

n(O₂) = 2.6 x 10⁻⁴ mol

n(N₂) = 5.44 x 10⁻⁴ mol

Thus, the total number of moles (nt) is calculated as the sum of the number of moles of the gases in the mixture:

nt = n(O₂) + n(N₂) = 2.6 x 10⁻⁴ mol + 5.44 x 10⁻⁴ mol = 8.04 x 10⁻⁴ mol

Finally, the mole fraction of each gas is calculated as the ratio between the number of moles of each gas and the total number of moles:

X(O₂) = n(O₂)/nt = 2.6 x 10⁻⁴ mol/(8.04 x 10⁻⁴ mol) = 0.323

X(N₂) = n(N₂)/nt = 5.44 x 10⁻⁴ mol/(8.04 x 10⁻⁴ mol) = 0.677

5 0

3 years ago