The period of a simple pendulum is given by:
where L is the length of the pendulum and g is the gravitational acceleration.
The pendulum in our problem makes one complete vibration in 0.333 s, so its period is T=0.333 s. Using this information, we can re-arrange the previous formula to find the length of the pendulum, L:
How do we find the Average Speed ?
The Average Speed is the distance traveled for the object, divided by the elapsed time taken to travel that distance, so the formula is :
<em>S = D / T</em>
where S = Average Speed, D = Distance, and T = Times
Here the object is the ball, the distance is 9 meters and the time elapsed for the ball to roll down the street is 3.5 seconds. Applying the formula we get :
S = 9 / 3.5 ≈ 2.6 metres per second
The ≈ symbols (which is the <em>wavy equal sign</em>) means we can't write the exact result, because there is an infinite quantity of numbers after the decimal point. So we need to give an approximation, since the result is 2.57142857142857...etc. we choosed to round up the result to 2.6.
Answer:
V = ω A sin ω t can be used to describe SHM
When sin ω t = 1 (the maximum value possible)
V = ω A at equilibrium sin ω t = 1
Explanation:
force = mass × acceleration
Solving for acceleration:
acceleration = force / mass
To find the acceleration, divide each force by the mass. For example:
a = 480 N / 62 kg
a = 7.74 m/s²
Answer: The volume is: " 1.430 cm³ " .
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Explanation:
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Volume, " V = ? ; (unknown, we need to solve for this).
Density, "D = 19.32 g / cm³ ;
mass , "m" = 27.63 g ;
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The formula for density is:
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D = m / V ; Divide each side of the equation by: "(1/m)" ;
to isolate " V" on one side of the equation; and to solve for "V" ;
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1/m)*D = (1/m) * (m / V) ;
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to get:
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D/m = ; ↔ 1 / V ; Take the reciprocal of EACH SIDE; to isolate "V" on each side of the equation:
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m / D = V/1 ↔ V = m / D ;
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V = m / D ;
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Now, plug in our given values for mass, "m" ; and Density, D"; to solve for "Volume, V " ;
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V = m / D = (27.63 g) ÷ (<span>19.32 g / cm</span>³) ;
= (27.63 g) * (1 cm³ / 19.32 g) ;
= (27.63 ÷ 19.32) cm³ ;
= 1.4301242236024845 cm³ ;
→ Round to "4 significant figures" ;
= 1.430 cm³ .
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The volume is: " 1.430 cm³ " .
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