at t=T/6, total distance covered= 2*pi*r/6 and displacement= r
difference of them = 2*t
so, 2*pi*r/6- r =2(1/6)=1/3
r=1/(pi-3)=7.062
You could be counting while running
Try looking it up. that might help
Answer:
The skier’s speed on the two level stretches are 22.13 m/s and 27.29 m/s.
Explanation:
Given that,
Slope down = 32°
Height = 25 m
Before leveling,
Slope down = 20°
Height = 38 m
We need to calculate the skier’s speed on the two level stretches
Using formula of energy



For first stretch,
Height = 25 m
Put the value into the formula


For second stretch,
Height = 38 m
Put the value into the formula


Hence, The skier’s speed on the two level stretches are 22.13 m/s and 27.29 m/s.
64. 16x16 = 4 so 9x9 divided by 2 equals 7