Question

A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring 17 feet. The ball is started in motion from the equilibrium position with a downward velocity of 4 feet per second. The air resistance (in pounds) of the moving ball numerically equals 4 times its velocity (in feet per second) . Suppose that after t seconds the ball is y feet below its rest position. Find y in terms of t. (Note that the positive direction is down.) Take as the gravitational acceleration 32 feet per second per second.

Answer 1

Answer:

• y = (0 - 4 * sqrt(6)/48)  * exp ((-16 -4 * sqrt(6) )*t + (0 + 4 * sqrt (6) /48) * exp ((-16 + 4 * sqrt (6)) * t)

Explanation:

• Assume that the gravitational acceleration is 32 feet per second square.
• y = (0 - 4 * sqrt(6)/48)  * exp ((-16 -4 * sqrt(6) )*t + (0 + 4 * sqrt (6) /48) * exp ((-16 + 4 * sqrt (6)) * t)

Answer 2

twelve because it is the answer