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Alja [10]
2 years ago
15

A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring 17 feet. The ball is started in moti

on from the equilibrium position with a downward velocity of 4 feet per second. The air resistance (in pounds) of the moving ball numerically equals 4 times its velocity (in feet per second) . Suppose that after t seconds the ball is y feet below its rest position. Find y in terms of t. (Note that the positive direction is down.) Take as the gravitational acceleration 32 feet per second per second.
Physics
2 answers:
valkas [14]2 years ago
7 0

Answer:

  • y = (0 - 4 * sqrt(6)/48)  * exp ((-16 -4 * sqrt(6) )*t + (0 + 4 * sqrt (6) /48) * exp ((-16 + 4 * sqrt (6)) * t)

Explanation:

  • Assume that the gravitational acceleration is 32 feet per second square.
  • y = (0 - 4 * sqrt(6)/48)  * exp ((-16 -4 * sqrt(6) )*t + (0 + 4 * sqrt (6) /48) * exp ((-16 + 4 * sqrt (6)) * t)
Romashka-Z-Leto [24]2 years ago
5 0

twelve because it is the answer

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