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2 years ago

Match each rock with the correct description.

Physics

2 answers:

liberstina [14]2 years ago

8 0

Answer:

1- Extrusive igneous rock

2- Intrusive igneous rock

3- Organic sedimentary rocks

4- Clastic sedimentary rocks

5- Chemical sedimentary rock

6- Metamorphic rock

Explanation:

Extrusive igneous rock- This are the igneous rocks that are formed when magma ejects out to the surface and quickly solidifies. Since they comes out to the surface, so they are considered to be extrusive igneous rocks. This type of rocks are comprised of smaller crystals due to the faster rate of cooling. For example, basalt.

Intrusive igneous rock- This are the type of igneous rocks that are formed due to the crystallization of magma at a certain depth. This rocks are made up of coarser crystals due to the slow rate of cooling. For example, granite.

Organic sedimentary rocks- This are the type of sedimentary rocks that are comprised of fossil or organic compound. These fossils are trapped about millions of years back. This type of rocks containing fossils are important for determining the past environment, climate and food habitat of these fossil organisms. For example Limestone.

Clastic sedimentary rocks- This are the sedimentary rocks that are formed from the compaction and lithification of loose sediments or broken rock materials. For example, sandstone.

Chemical sedimentary rock- This are the type of sedimentary rocks that are formed from the minerals (crystals). This minerals are made up of the elements that undergoes dissolution in water. For example, oolitic limestone.

Metamorphic rock- This are the secondary rock, either derived from the igneous, sedimentary or other metamorphic rock. These rocks are formed due to the extreme pressure, temperature condition. They are also known as the secondary rocks. For example, Quartzite.

xeze [42]2 years ago

5 0

Answer:

Explanation:

1. cools quickly on the earth's surface

Extrusive igneous rock

2. cools slowly beneath the earth's surface

Intrusive igneous rock

3. formed from the remains of living organisms

Organic sedimentary rocks

4. formed from pieces of other rocks cemented together

Clastic sedimentary rock

5. formed when dissolved minerals harden

Chemical sedimentary rock

6. formed from heat and pressure

Metamorphic rocks

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Lunna [17]

Answer:

a. $v=3.11mls$ , $29.4^{0}$

b. $K.E =-697.8J$

Explanation:

To calculate the values in the question, a deep understanding of perfect inelastic collision is important.

When two bodies undergo inelastic collision, two important parameters must be well understood i.e

Momentum: the momentum is always conserved in perfectly inelastic collision. i.e the total momentum after collision is the sum of the individual momentum before collision

Kinetic energy: Kinetic energy is not conserved due to dissipative force.

a.To calculate the velocity, we first find the total momentum before collision

Momentum of player 1 $p_{1} =mv=95kg*5m/s\\p_{1} =475kgm/s\\$

Momentum of player 2 $p_{2} =mv=90kg*3m/s\\p_{1} =270kgm/s\\$

Hence the total momentum $p_{12}=p_{1}+p_{2}\\$

Note, since the direction of movement before collision is due south and due north respectively we have to represent the velocity using the rectangular coordinate

Hence $p_{12}=(m_{1}+m_{2})v=p_{1}i+p_{2}j\\$

$(95+90)v=475i+270j\\$

$v=2.57i+1.45j\\$

solving for the resultant velocity, we have

$v=\sqrt{2.75^{2} +1.45^{2}}\\ v=3.11mls$

To calculate the direction of movement, we have

$\alpha =tan^{-1}=\frac{v_{j} }{v_{i}}\\ \alpha =tan^{-1}=\frac{1.45}{2.57}\\\alpha =29.4^{0}$

b. to calculate the decrease in total kinetic energy, before collision, the total kinetic was

$K.E_{initial} =\frac{1}{2}m_{1}v_{1}^{2}+\frac{1}{2}m_{2}v_{2}^{2}.\\K.E_{initial} =((1/2)*95*5^{2})+((1/2)*90*3^{2})\\K.E_{initial} =1187.5+405\\K.E_{initial} =1592.5J\\$

And the final kinetic energy after collision is

$K.E_{final} =\frac{1}{2}(m_{1}+m_{2} )v^{2}\\ K.E_{final} =\frac{1}{2}(95+90)* 3.11^{2}\\ K.E_{final} =894.7J$

The decrease in Kinetic energy is

$K.E =K.E_{final}- K.E_{initial}=894.7-1592.5$

$K.E =-697.8J$

The negative sign indicate a decrease in Kinetic energy

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2 years ago

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$E_{thread}$ = {2.5 / (22 π ε° X 0.07 ) ; 0}

Answer 2) $E_{q}$ = {2.3 / (4 2 π ε°) ( - 7/ (√(84); -12 / (√84))

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Answer:

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