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sasho [114]
3 years ago
12

Match each rock with the correct description.

Physics
2 answers:
liberstina [14]3 years ago
8 0

Answer:

1- Extrusive igneous rock

2- Intrusive igneous rock

3- Organic sedimentary rocks

4- Clastic sedimentary rocks

5- Chemical sedimentary rock

6- Metamorphic rock

Explanation:

Extrusive igneous rock- This are the igneous rocks that are formed when magma ejects out to the surface and quickly solidifies. Since they comes out to the surface, so they are considered to be extrusive igneous rocks. This type of rocks are comprised of smaller crystals due to the faster rate of cooling. For example, basalt.

Intrusive igneous rock- This are the type of igneous rocks that are formed due to the crystallization of magma at a certain depth. This rocks are made up of coarser crystals due to the slow rate of cooling. For example, granite.

Organic sedimentary rocks- This are the type of sedimentary rocks that are comprised of fossil or organic compound. These fossils are trapped about millions of years back. This type of rocks containing fossils are important for determining the past environment, climate and food habitat of these fossil organisms. For example Limestone.

Clastic sedimentary rocks- This are the sedimentary rocks that are formed from the compaction and lithification of loose sediments or broken rock materials. For example, sandstone.

Chemical sedimentary rock- This are the type of sedimentary rocks that are formed from the minerals (crystals). This minerals are made up of the elements that undergoes dissolution in water. For example, oolitic limestone.

Metamorphic rock- This are the secondary rock, either derived from the igneous, sedimentary or other metamorphic rock. These rocks are formed due to the extreme pressure, temperature condition. They are also known as the secondary rocks. For example, Quartzite.

xeze [42]3 years ago
5 0

Answer:

Explanation:

1. cools quickly on the earth's surface

Extrusive igneous rock

2. cools slowly beneath the earth's surface

Intrusive igneous rock

3. formed from the remains of living organisms

Organic sedimentary rocks

4. formed from pieces of other rocks cemented together

Clastic sedimentary rock

5. formed when dissolved minerals harden

Chemical sedimentary rock

6. formed from heat and pressure

Metamorphic rocks

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GalinKa [24]

Answer;

-  No, Two vectors of unequal magnitude can never sum to zero.

Explanation;

-Two vectors of equal magnitude that are pointing in opposite directions will sum to zero.

-Two vectors of unequal magnitude can never sum to zero. If they point along the same line, since their magnitudes are different, the sum will not be zero.

- If they point in different directions, then you can always decompose one vector into two components: one along the other vector and one perpendicular to the other vector. In this case, the perpendicular component can never be eliminated.

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3 years ago
A table exerts a 4.0 Newton force on a book which lies at rest on its top. The force exerted by the book on the table is
SOVA2 [1]
I believe the correct answer from the choices listed above is the third option. <span>The force exerted by the book on the table is equal to the force exerted by the table which is 4.0 N. The book does not move so it must be that the forces are balanced. Hope this answers the question.</span>
4 0
3 years ago
Read 2 more answers
A tennis ball connected to a string is spun around in a vertical, circular path at a uniform speed. The ball has a mass m = 0.15
Oksanka [162]

1) 5.5 N

When the ball is at the bottom of the circle, the equation of the forces is the following:

T-mg = m\frac{v^2}{R}

where

T is the tension in the string, which points upward

mg is the weight of the string, which points downward, with

m = 0.158 kg being the mass of the ball

g = 9.8 m/s^2 being the acceleration due to gravity

m \frac{v^2}{R} is the centripetal force, which points upward, with

v = 5.22 m/s being the speed of the ball

R = 1.1 m being the radius of the circular trajectory

Substituting numbers and re-arranging the formula, we find T:

T=mg+m\frac{v^2}{R}=(0.158 kg)(9.8 m/s^2)+(0.158 kg)\frac{(5.22 m/s)^2}{1.1 m}=5.5 N

2) 3.9 N

When the ball is at the side of the circle, the only force acting along the centripetal direction is the tension in the string, therefore the equation of the forces becomes:

T=m\frac{v^2}{R}

And by substituting the numerical values, we find

T=(0.158 kg)\frac{(5.22 m/s)^2}{1.1 m}=3.9 N

3) 2.3 N

When the ball is at the top of the circle, both the tension and the weight of the ball point downward, in the same direction of the centripetal force. Therefore, the equation of the force is

T+mg=m\frac{v^2}{R}

And substituting the numerical values and re-arranging it, we find

T=m\frac{v^2}{R}-mg=(0.158 kg)\frac{5.22 m/s)^2}{1.1 m}-(0.158 kg)(9.8 m/s^2)=2.3 N

4) 3.3 m/s

The minimum velocity for the ball to keep the circular motion occurs when the centripetal force is equal to the weight of the ball, and the tension in the string is zero; therefore:

T=0\\mg = m\frac{v^2}{R}

and re-arranging the equation, we find

v=\sqrt{gR}=\sqrt{(9.8 m/s^2)(1.1 m)}=3.3 m/s

7 0
3 years ago
A 4.00-m long rod is hinged at one end. The rod is initially held in the horizontal position, and then released as the free end
Natalka [10]

Answer:

The angular acceleration α = 14.7 rad/s²

Explanation:

The torque on the rod τ = Iα where I = moment of inertia of rod = mL²/12 where m =mass of rod  and L = length of rod = 4.00 m. α = angular acceleration of rod

Also, τ = Wr where W = weight of rod = mg and r = center of mass of rod = L/2.

So Iα = Wr

Substituting the value of the variables, we have

mL²α/12 = mgL/2

Simplifying by dividing through by mL, we have

mL²α/12mL = mgL/2mL

Lα/12 = g/2

multiplying both sides by 12, we have

Lα/12 × 12 = g/2 × 12

αL = 6g

α = 6g/L

α = 6 × 9.8 m/s² ÷ 4.00 m

α = 58.8 m/s² ÷ 4.00 m

α = 14.7 rad/s²

So, the angular acceleration α = 14.7 rad/s²

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Answer:

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Hope that was helpful.Thank you!!!

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