Between phosphorous, sulfur, chlorine and argon, argon is the element that's the least likely to form an ionic bond with sodium.
Answer:
Sometimes you just have to get yourself hard to understand what you are really going through and how much you have done and how hard you are.
Explanation:
Tbh not all quotes are easy to express but this one sounds really interesting.
But in my opinion this is the best I could describe
Hope you agree. Let me know :)
Yes. It is only through creativity that scientific inquiry exists. Someone had the wacky creative idea that there should be something that is so strong, and inflammable, and just generally amazing like a super... thing! And tadaaah, we have Kevlar. The stuff in bullet proof vests.
Answer:
The correct answer is 5 moles of CO2 are produced.
Explanation:
The given reaction:
CH₄ (g) + 2O₂ (g) ⇔ CO₂ (g) + 2H₂O (g)
The given reaction is an illustration of a combustion reaction. Any reaction in which a substance is burnt in excess of oxygen to generate water and carbon dioxide is termed as a combustion reaction. From the given equation, it is clear that the moles of the formation of the products are in the ratio 1: 2, that is, if 10 moles of H₂O is produced, the production of 5 moles of CO₂ will be produced.
Let us multiply, the given equation with 5 we get,
5CH₄ + 10O₂ ⇔ 5CO₂ + 10H₂O
Hence, it is clear that with the formation of 10 moles of H₂O, formation of 5 moles of CO₂ will also take place.
Answer:
O, N, C, H
Explanation:
Electronegativity of an element is the property that combines the ability of its atom to lose or gain electrons. It measures the relative tendency with which the atoms of the element attracts valence electrons in a chemical bond.
On the periodic table, Electronegativity increases across the period but decreases down a group.
To solve the given problem, let us use thE Pauling's table of electronegativities to compare the electronegativities of the elements.
On the table:
C = 2.5
H = 2.1
O = 3.5
N = 3.0
In terms of decreasing electronegativities, the atoms are arranged as:
O N C H
