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6 0

3 years ago

The mass of a proton is 1833 times larger than the mass of an electron. When a proton an electron interact with each other the o

Ad libitum [116K]

B. Exactly the same as the electric force of the electron on the proton.

<u>Explanation:</u>

Even if the mass of proton is increased or decreased, the force between electron and proton will remain the same because force is dependent on the charge of the object and distance between them. The force between the charges is independent of their masses. So, even if the mass of a proton is 1833 times larger than the mass of an electron, the force between them will be same.

According to Coulomb's law:

$F = k\frac{q_1q_2}{r^2}$

where,

F is the force

q₁ and q₂ are the charges

r is the distance between the charges

8 0

3 years ago

What is the simplest relationship between the angular wavenumber k and just one of the other kinematic variables?

Inessa [10]

Answer : $k=\dfrac{\omega}{k}$

Explanation :

The word kinematics means the study of motion. Kinematic variables gives the description of the motion of the body.

Displacement, Velocity, acceleration and time are associated with the motion of particle.

Wavenumber is defined as the frequency of wave, which is measured in cycles per unit distance.

Wave number is also defines as:

$k=\dfrac{2\pi}{\lambda}$

where, $\lambda$ is wavelength

$k=\dfrac{2\pi}{\lambda}\times \dfrac{T}{T}$

since, $\dfrac{2\pi}{T}=\omega \ and\ \dfrac{1}{V}=\dfrac{T}{\lambda}$

So, $k=\dfrac{\omega}{V}$

Where, $\omega$ is angular frequency and $V$ is velocity of wave.

Hence, the relationship between the angular wavenumber k and and kinamatic variable V is

$k=\dfrac{\omega}{V}$

6 0

3 years ago

What happens to water when it changes to ice?

Vinvika [58]

Answer:

Its density decreases, and its volume increases

Explanation:

Density is defined as Mass/Volume. What happens when water transforms into ice is that its density decreases because the volume the molecules now occupy increases.

The denominator of the rational expression $\frac{Mass}{Volume}$ is now larger (while the numerator stays the same), so the quotient gives a smaller number.

3 0

3 years ago

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