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3 years ago

Help asap please ty :)

Chemistry

1 answer:

Mariulka [41]3 years ago

6 0

Square root of 16 is 4 so I assume the answer would just be -4

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A red blood cell placed in saline solution will shrink.<br> True or false? Explain please?

Scorpion4ik [409]

Yes a red blood cell placed in a sline solution shrinks because of the process of osmosis.

5 0

3 years ago

How many grams of Na2CO3 must be dissolved into 155g of water to create a solution with a molarity of 8.20 mol/kg

zhannawk [14.2K]

Answer:

135g Na2CO3

Explanation:

I'm going to assume you mean Molality which is mol solute/kg solvent

Molarity would be mol soute/ L solution

we know we have 155g of water which is .155 kg

essentially we have the equation:

mol/kg = 8.20

we substitute .155 in for kg and get:

mol/.155 = 8.20

Solving this gives mol = 1.271

now we must convert to grams using the molar mass

Molar mass Na2CO3 = 106G/mol

so to cancel moles we multiply:

1.271mol x 106g/mol

= 135g

4 0

3 years ago

PLSSS HELP FAST

Aliun [14]

Note the formula

$\boxed{\sf Mass\:no=No\:of\:protons+No\:of\:neutrons}$

For X:-

No of protons:-

$\\ \sf\longmapsto 19-10=9protons$

It is Fluorine.

For Y:-

No of protons:-

$\\ \sf\longmapsto 16-8=8protons$

It is Oxygen.

Option D is correct

7 0

2 years ago

When the chemicals iron sulfide (FeS) and hydrochloric acid (HCl) are combined, bubbles appear from the mixture. 1. Does the app

Fudgin [204]

The reaction of iron sulfide (FeS) with hydrochloric acid (HCl) results in the formation of ferrous chloride (FeCl2) and hydrogen sulfide (H2S) gas. The reaction can be shown as follows:

FeS (s) + HCl(aq) ---- FeCl2(s) + H2S(g)

The bubbles indicate the formation of H2S gas which is a chemical change. The formation of bubbles indicates this change as it suggests that the reactants are combing to form products i.e. it signals a chemical reaction.

8 0

3 years ago

This is my chemistry worksheet. It's a new topic my teacher will barely review with us. Help please???

TEA [102]

So to balance an equation, you need to get the same amount of each type of element on either side of the --> . So you pretty much are given the subscripts in the equations and you need to add coefficients (just normal numbers) in front of any formula that needs it, keeping anything balance.
$KCl_{3} + O_{2} -\ \textgreater \ KCl_{3}$
turns into
$2KCl_{3}+ 3O_{2} -> 2KCl_{3}$

These coefficient numbers are the molar ratios, so 2 moles of KCl3 for every 3 moles of O2 so 1. 3:2

Then you can use these ratios of find out how many moles of one thing are needed if you are given the amount of another.
$\frac{moles of element 1}{cofficient 1} = \frac{moles of element 2}{cofficient 2}$
and use cross multiplication to solve for whatever you don't know

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6 0

3 years ago