Answer:
0,508g of H₂O₂
Explanation:
For the reaction:
2KMnO₄(aq) + H₂O₂(aq) + 3H₂SO₄(aq) → 3O₂(g) + 2MnSO₄(aq) + K₂SO₄(aq) + 4H₂O(l)
2 moles of KMnO₄ react with 1 mol of H₂O₂.
In the titration, moles of KMnO₄ required were:
1,68M×0,0178L = 0,0299 moles of KMnO₄. Moles of H₂O₂ are:
0,0299 moles of KMnO₄×
= 0,01495 moles of H₂O₂. As molar mass of H₂O₂ is 34,01g/mol, mass of H₂O₂ was dissolved is:
0,01495 moles of H₂O₂×
= <em>0,508g of H₂O₂</em>
Answer:
yes. cats love mac and cheese
Transverse can travel through solids(but not liquids and gas) and longitude can travel through any matter.
The mass of a present which has a density of 2.15 kg/L and volume of 3650 mL is 7.74 kg.
<h3>How do we calculate mass?</h3>
Mass of any substance will be calculate by using the density and volume by using the below equation as:
Density = Mass / Volume
Given that,
Density of Christmas present = 2.15 kg/L
Volume of present = 3,650 mL = 3.6L
On putting values, we get
Mass = (2.15)(3.6) = 7.74
Hence required mass of Christmas present is 7.74 kg.
To know more about density, visit the below link:
brainly.com/question/10441359
#SPJ1
