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Evgen [1.6K]
4 years ago
5

What is measurement​

Physics
1 answer:
Mrrafil [7]4 years ago
4 0

Answer:

what makes u think u can't search tht up on google?

Explanation:

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Anybody knows the answers?
ycow [4]
Lol i'm doing the same packet for class.
35- A
36- C
37- B
38- B
39- D
40- B
41- D
5 0
3 years ago
Read 2 more answers
14 What is the weight of each of
Gwar [14]

Explanation:

On earth,

g=10 m/s^2

When M=2 kg,

weight on earth=2×10

=20N

When M=3.5 kg,

weight on Earth=3.5×10

=35N

When M=5kg,

weight on Earth=5.25×10

=52.5N

5 0
3 years ago
A Eureka can of mass 60g and cross sectional area of 60 square centimeters is fillied with water of density 1g/ cubic centimeter
Natalka [10]

a.600 cm³

b. 2.5 g/cm³

c.  2.0775 kg

<h3>What is Eureka moment?</h3>

In Physics, this Archimedes' Eureka moment is called the Archimedes Principle, which states that when a body is immersed in a liquid, it experiences an upward buoyant force, which is equal to the weight of the liquid displaced by the body.

According to the question

Mass of Eureka is 60g

Cross sectional area  is 60 square centimeters

Mass of steel piece is 20g

Density = 8g /cubic centimeter

a)The total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can.

To find the mass of the water but we can easily find if we know the volume of the can.

In order to calculate the volume we would have to multiply the area of the cross section by the height.

Here,

60cm² x 10cm = 600 cm³

To find the mass that water has in this case we have to multiply the water's density by the volume,

so we get....

\frac{1g}{cm^3} x 1000 = 1000g or 1kg

Now can calculate the total mass of the can before the metal was lowered, by adding the mass of the water to the mass of the can.

So we get....

1000g + 60g = 1060g or 1.06kg

b)The volume of the water that over flowed will be equal to the volume of the metal piece since, when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle".

Knowing this we just have to calculate the volume of the metal piece an that will be the answer.

So this time in order to find volume we will have to divide the total mass of the metal piece by its density.

So we get

20g ÷ \frac{8}{cm^3} = 2.5 g/cm³

c)Now to find out the total mass of the can after the metal piece was lowered we would have to add the mass of the can itself, mass of the water inside the can, and the mass of the metal piece.

We know the mass of the can, and the metal piece but we don't know the mass of the water because when we lowered the metal piece some of the water overflowed, and as a result the mass of the water changed. So now we just have to find the mass of the water in the can keeping in mind the fact that 2.5 overflowed.

So now we the same process as in number a) just with a few adjustments.

\frac{1g}{cm^3} x (1000 - 2.5) = 997.5g

So now that we know the mass of the water in the can after we added the metal piece we can add all the three masses together (the mass of the can.

The mass of the water, and the mass of the metal piece.

Hence,

1060g + 997.5g + 20g = 2077.5 g or  2.0775 kg

Learn more about Archimedes Principle here:

brainly.com/question/13106989

#SPJ1

4 0
2 years ago
A comet is cruising through the solar system at a speed of 50,000 kilometers per hour foe 4 hours time. What is the total distan
Triss [41]

Answer:

<em>The distance covered by comet is </em>200,000 km

Explanation:

Speed is defined as the rate of change of distance with time. It is given by the equation speed= \bold{\frac{distance}{time}}

Thus distance= speed*time

In this problem it is given that speed of comet= \frac{50,000km}{hr}

time travelled by the comet= 4 hours

Thus distance= speed*time

                            = 500000*4

                            = \bold{200,000km}

5 0
3 years ago
The body falls in a free fall 11s.Calculate: a) from what height the body of the paddle) what path did it fall during the last s
JulsSmile [24]

Answer:

a) h = 593.50 m

b) h₁₁ = 103 m

c) vf = 107.91 m/s

Explanation:

a)

We will use second equation of motion to find the height:

h = v_{i}t + (\frac{1}{2})gt^2

where,

h = height = ?

vi = initial speed = 0 m/s

t = time taken = 11 s

g = 9.81 /s²

Therefore,

h = (0\ m/s)(11\ s) + (\frac{1}{2})(9.8\ m/s^2)(11\ s)^2\\\\

<u>h = 593.50 m</u>

b)

For the distance travelled in last second, we first need to find velocity at 10th second by using first equation of motion:

v_{f} = v_{i} + gt

where,

vf = final velocity at tenth second = v₁₀ = ?

t = 10 s

vi = 0 m/s

Therefore,

v_{10} = 0\ m/s + (9.81\ m/s^2)(10\ s)\\\\v_{10} = 98.1\ m/s

Now, we use the 2nd equation of motion between 10 and 11 seconds to find the height covered during last second:

h = v_{i}t + (\frac{1}{2})gt^2

where,

h = height covered during last second = h₁₁ =  ?

vi = v₁₀ = 98.1 m/s

t = 1 s

Therefore,

h_{11} = (98.1\ m/s)(1\ s) + (\frac{1}{2})(9.8\ m/s^2)(1\ s)^2\\\\

<u>h₁₁ = 103 m</u>

c)

Now, we use first equation of motion for complete motion:

v_{f} = v_{i} + gt

where,

vf = final velocity at tenth second = ?

t = 11 s

vi = 0 m/s

Therefore,

v_{f} = 0\ m/s + (9.81\ m/s^2)(11\ s)

<u>vf = 107.91 m/s</u>

8 0
4 years ago
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