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3 years ago

Other than exercises, what other factors do you think influences breathe/minute? why?

Chemistry

2 answers:

den301095 [7]3 years ago

5 0

Answer:

I think probably diet because the type of food you put in your body (if it has high calorie or sodium) can severley affect your overall health and therefore affect your bpm(beats per minute)

Explanation:

Reptile [31]3 years ago

4 0

Answer:

Running is the factor that I think influences breathe/minute

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telo118 [61]

It would be 399.88 g/mol.

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3 years ago

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natta225 [31]

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Explanation:

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2 years ago

Consider the following solutions: 0.010 m Na3PO4 in water 0.020 m CaBr2 in water 0.020 m KCl in water

Helen [10]

Answer:

a) KI and Na₃PO₄

b) HF

c) CaBr₂

Explanation:

The depression in freezing point, relative lowering of vapor pressure and elevation in boiling point are colligative properties.

The collegative properties depend upon the number of solute particles.

Let us see the concentration of particles in each of the given solutions:

a) 0.010 m Na₃PO₄ in water : each molecule will give three sodium ions and one phosphate ion.

So the concentration of particles in the solution = 4 X 0.01 = 0.04 m

b) 0.020 m CaBr₂ in water : each molecule will give one calcium ion and two bromide ion thus the concentration of particles in the solution

= 3 X 0.02 = 0.06 m

c) 0.020 m KCl in water: each molecule gives two ions thus the concentration of solution = 2 X 0.02 = 0.04 m

d) 0.020 m HF (weak acid) in water: the acid is weak, so each molecule will not give two ions completely (complete dissociation will not be observed). concentration of solution will be more than 0.02 but less than 0.04.

a) Both KCl and Na₃PO₄ will have same boiling point as 0.04 C₆H₁₂O₆.

b) the solution with least concentration of solute will have highest pressure. Thus HF is the answer,

c) the largest depression will be in the solution with highest solute concentration: Answer: CaBr₂.

8 0

2 years ago

It takes 42.25 ml of 0.0500 M Na2S2O3 solution to completely react with the iodine present in a 150.0 ml iodine solution. How ma

svlad2 [7]

Answer:

There were 0.268 grams I2 present

Explanation:

Step 1: Data given

Volume of Na2SO3 = 42.25 mL = 0.04225 L

Molarity of Na2SO3 = 0.0500 M

Volume of iodine = 150.0 mL

Step 2: The balanced equation

I2 + 2 Na2SO3 → Na2S2O6 + 2 NaI

Step 3: Calculate moles of Na2SO3

Moles Na2SO3 = molarity * volume

Moles Na2SO3 = 0.0500 M * 0.04225 L

Moles Na2SO3 = 0.0021125 moles

Step 4: Calculate moles I2

For 1 mol I2 we need 2 moles Na2SO3

For 0.0021125 moles Na2SO3 we have 0.00105625

Step 5: Calculate mass of I2

Mass I2 = moles * molar mass

Mass I2 = 0.00105625 * 253.8 g/mol

Mass I2 = 0.268 grams

There were 0.268 grams I2 present

3 0

3 years ago

Read 2 more answers

If 6 moles of a compound produce 84 J of energy, what is the Alreaction in

Naddik [55]

answer : 14 J/mol

J/mol unit in the answers gives the hint as to what you should do which is divide the J from mol

J ÷ mol

84 ÷ 6 = 14

4 0

2 years ago

Other than exercises, what other factors do you think influences breathe/minute? why?​

Other than exercises, what other factors do you think influences breathe/minute? why?