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We have that the the molarity of methanol in the solution is mathematically given as
Morality=7.91mol/l
<h3>Chemical Reaction</h3>Question Parameters:
An <u>aqueous </u><em>solution </em>of methanol (MM = 32.04 g/mol)
A molality of 8.83 m and a density of 1.15 g/mL.
Generally the equation for the is mathematically given as
where
Mass of solution=(100+282.2)
Mass of solution=1289.9
Volume=1289.9/1.15
Volume=1.115L
Therefore
Morality=8.83/1.115
Morality=7.91mol/l
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Answer:
See Below.
Explanation:
Recall that molarity is defined by moles of solute over liters of solution (mol/L).
Therefore, to make 90.0 mL of 2.0 M MgSO₄, we will need:
Convert this amount to grams. The molecular weight of MgSO₄ is 120.38 g/mol:
Therefore, to make the solution, we can add 22 grams of MgSO₄ into a graduated cylinder, then mix and dilute the solution with distilled water until we reach 90.0 mL.