Answer:
Secondary current is 8A
Explanation:
Data :
Primary supply = Vp = 240 V
Secondary supply = Vs = 60V
Primary current = Ip = 2A
Secondary current = Is = ?
Formula : Vp × Ip = Vs × Is
So for secondary current formula becomes
Is = (Vp/Vs)×Ip = (240/60) × 2
Is = 4 × 2 = 8A
I think the answer is eustress and distress
Answer:
A) a_c = 1.75 10⁴ m / s², B) a = 4.43 10³ m / s²
Explanation:
Part A) The relation of the test tube is centripetal
a_c = v² / r
the angular and linear variables are related
v = w r
we substitute
a_c = w² r
let's reduce the magnitudes to the SI system
w = 4000 rpm (2pi rad / 1 rev) (1 min / 60s) = 418.88 rad / s
r = 1 cm (1 m / 100 cm) = 0.10 m
let's calculate
a_c = 418.88² 0.1
a_c = 1.75 10⁴ m / s²
part B) for this part let's use kinematics relations, let's start looking for the velocity just when we hit the floor
as part of rest the initial velocity is zero and on the floor the height is zero
v² = v₀² - 2g (y- y₀)
v² = 0 - 2 9.8 (0 + 1)
v =√19.6
v = -4.427 m / s
now let's look for the applied steel to stop the test tube
v_f = v + a t
0 = v + at
a = -v / t
a = 4.427 / 0.001
a = 4.43 10³ m / s²
Answer:
Part a)

Part b)

Part c)
So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass
Explanation:
Part a)
Let say the collision between Moose and the car is elastic collision
So here we can use momentum conservation


also by elastic collision condition we know that

now we have

now we have

Now loss in kinetic energy of the car is given as


so fractional loss in energy is given as



Part b)
Let say the collision between Camel and the car is elastic collision
So here we can use momentum conservation


also by elastic collision condition we know that

now we have

now we have

Now loss in kinetic energy of the car is given as


so fractional loss in energy is given as



Part c)
So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass
A. dependent variable
As the the independent variable (i.e. number of cats being sold) increases, the dependent variable (i.e. money made) will also increase. You can have 1,000,000 cats for sale and make no money, but you cannot make money without having sold some cats first.
Hope my weird example helped!