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shutvik [7]
3 years ago
9

What property of a solution is the same before and after it is diluted?

Chemistry
1 answer:
N76 [4]3 years ago
3 0

<em>Answer</em>

A) amount of solute

<em>Explanation</em>

Dilution is adding more solvent to a solution to decrease the concentration of solute in a solution. The amount of solute does not change although the concentration, amount of solvent and the total volume does change.

An example of this would be adding more water (solvent) to lemonade to decrease the concentration of lemon juice (solute). Obviously this would increase the total volume because you are adding more water to the solution.

<em>hope this helps!</em>

<em>have a great day :)</em>

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If a car weighs 300 kg, and gravity causes it to accelerate downward at 9.8 m/s2. What is the gravitational force on the
JulsSmile [24]

Answer:

gravity pulls

Explanation:

gravity pulls you down

8 0
3 years ago
If you have 5.22*1022 molecules of glucose (C6H12O6) how many grams is this?
lianna [129]

Answer:

5.22*1022 molecules of glucose (C6H12O6)  is equal to 15.08 grams

Explanation:

Number of molecule of glucose in one mole = 6.023 * 10^{23}

Now mass of one mole of glucose = 180 grams

Number of moles in 6.023 * 10^{23} molecules of glucose = 1

Number of moles in 1 molecules of glucose =  \frac{1}{6.023 * 10^{23}}

Number of moles in 5.22 * 10^{22} molecules of glucose =  \frac{5.22* 10^{22}}{6.023 * 10^{23}}  = 0.083 moles

Weight of 0.083 moles

= 0.083 * 180\\= 15.08grams

7 0
3 years ago
Two moles of a monatomic ideal gas are contained at a pressure of 1 atm and a temperature of 300 K; 34,166 J of heat are transfe
anygoal [31]

Answer:

Final temperature is 302 K

Explanation:

You can now initial volume with ideal gas law, thus:

V = \frac{n.R.T}{P}

Where:

n are moles: 2 moles

R is gas constant: 0,082 \frac{atm.L}{mol.K}

T is temperature: 300 K

P is pressure: 1 atm

V is volume, with these values: <em>49,2 L</em>

The work in the expansion of the gas, W, is: 1216 J - 34166 J = <em>-32950 J</em>

This work is:

W = P (Vf- Vi)

Where P is constant pressure, 1 atm

And Vf and Vi are final and initial volume in the expansion

-32950 J = -1 atm (Vf-49,2L) × \frac{101325 J}{1 atm.L}

Solving: <em>Vf = 49,52 L</em>

Thus, final temperature could be obtained from ideal gas law, again:

T = \frac{P.V}{n.R}

Where:

n are moles: 2 moles

R is gas constant: 0,082 \frac{atm.L}{mol.K}

P is pressure: 1 atm

V is volume: 49,52 L

T is final temperature: <em>302 K</em>

<em />

I hope it helps!

4 0
3 years ago
Can someone help me please:)
docker41 [41]

Answer:

what we ain't that smart

5 0
3 years ago
Which of the following air pollutants causes a reddish-brown haze in the sky?
Evgen [1.6K]
I would say A. Sulfur dioxide. Local coal burning power plants have been known to change the color of the sky.
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4 years ago
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