All categories

3 years ago

Which of the following DOES NOT have 2 significant

1 answer:

4 0

Significant figures are the digits that come after the first non-zero digit. The second value has 11 significant figures and is therefore the correct answer. However, the fourth answer has 4 significant figures and would also be a correct answer. So I don’t know if perhaps there has been a typo or a mistake in the question but with what you have provided here, both these answer have more than 2 significant figures.

You might be interested in

How many moles of N2 are need to fill a 35 L tank at standard temperature and pressure?

Tems11 [23]

1.56 moles of N2 are needed to fill a 35 L tank at standard temperature and pressure. Details about moles can be found below.

<h3>How to calculate number of moles?</h3>

The number of moles of a substance can be calculated using the following formula:

PV = nRT

Where;

P = pressure
V = volume
n = number of moles
R = gas law constant
T = temperature

At STP;

T = 273K
P = 1 atm
R = 0.0821 Latm/molK

1 × 35 = n × 0.0821 × 273

35 = 22.41n

n = 35/22.41

n = 1.56mol

Therefore, 1.56 moles of N2 are needed to fill a 35 L tank at standard temperature and pressure.

Learn more about number of moles at: brainly.com/question/14919968

#SPJ1

4 0

2 years ago

As a species evolve, they develop ________ and ________ others

Lerok [7]

New traits old traits to lose and save

5 0

3 years ago

Read 2 more answers

If you combine 320.0 ml of water at 25.00 °c and 120.0 ml of water at 95.00 °c, what is the final temperature of the mixture? us

Inga [223]

The heat from the hotter water will go into the colder water untl equilibrium is reached. Equilibrium is same temperature!

Now, the heat is proportional to the mass, the specific heat and the temperature difference. The specific heat does not matter since all is water, it will cancel out:

m_1 * c_H20 * ( T_final - T_1 ) = -m_2 * c_H20 * ( T_final - T_2)

Notice the minus, because one wins the heat of the one who loses it. In this way both sides have the same sign:

m_1*(T_final - T_1)=-m_2*(T_final-T_2), or after some simple algebra:

T_final = (m_1 * T_1 + m_2 * T_2 )/(m_1+m_2),

which looks like an arithmetic mean, and one could have gone for this, but the above shows all the work. Notice that if T_1=T_2, T_final=T_1 always, which makes sense.

Now you can convert volume to mass with the density, but since mass = density*volume and it is all water, the density will cancel out and you can work with volumes. If you prefer just say: 120 ml->120 g , etc ...

T_final = (120*95+320*25)/(320+120)=44.0909 degrees Celsius, or ~ 44.09 degrees with two decimal precision as your statement (beware of precision always!).

8 0

4 years ago

If 125 gram of 75% pure Caco3 is treated with 100 gram of Hcl to produce Cacl2 H20 and Co2 Find which one is limiting reactant

damaskus [11]

Answer:

Explanation:

7 0

3 years ago

The answer to question 2

Bad White [126]

Answer:

Explanation:

You will need a chemical equation with masses and molar masses, so let’s gather all the information in one place.

$M_{r}$ : 258.21 18.02

KAl(SO₄)₂·xH₂O ⟶ KAl(SO₄)₂ + xH₂O

Mass/g: 4.74 2.16

Step 1. Calculate the mass of the KAl(SO₄)₂.

Mass = 4.74 g – 2.16 g = 2.58 g.

Step 2. Calculate the moles of each product.

$\text{Moles of KAl(SO}_{4})_{2} = \text{2.58 g} \times \frac{\text{1 mol} }{\text{258.21 g}} = 9.992 \times 10^{-3} \text{ mol}$

$\text{Moles of H}_{2}\text{O} = \text{2.16 g} \times \frac{\text{1 mol} }{\text{18.02 g}} = \text{ 0.1200 mol}$

Step 3. Calculate the molar ratio of the two products.

$\frac{\text{Moles of KAl(SO}_{4})_{2}}{\text{Moles of H}_{2}\text{O}} = \frac{ 9.992 \times 10^{-3} \text{ mol}}{\text{ 0.1200 mol} } = \frac{1 }{12.01} \approx \frac{ 1}{ 12}$

1 mol of KAl(SO₄)₂ combines with 12 mol H₂O, so x = 12.

3 0

4 years ago