Answer:
a. reflection of all the light at a surface.
Explanation:
When light rays passing from the denser medium to the rarer medium and the angle of incidence is greater than the critical angle, the refraction of light does not take place and the incident ray is totally reflected back into the denser medium. This phenomenon is called total internal reflection.
There are two conditions that need to be fulfilled in order for the total internal reflection to take place:
1. The ray of light should be incident from denser to rarer medium.
2. The angle of incidence should be greater than the critical angle.
Therefore, the correct option will be:
<u>a. reflection of all the light at a surface.</u>
Answer:
Although this question is not complete, I would give a general solution to this kind of problems.
If y(t) describes the position of a body with time such that
y(t) = at^(n) + bt^(m) + C
Then
V(t) = dy(t)/dt = ant^(n-1) + bmt^(m-1)
Explanation:
As an example supplies the position of a particle is given by
y(t) = 4t³- 3t² + 9
V(t) = 4x3t²- 3x2t¹
V(t) = d(t)/dt = 12t² - 6t.
Another example,
If y(t) = 15t³ - 2t² + 30t -80
V(t) = d(t)/dt = 15x3t² - 4t +30 = 45t² + 4t + 30.
Basically, in the equations above the powers of t reduces by one when computing the velocity function from y(t) by differentiation (calculating the derivative of y(t)). The constant term C (9 and 80 in the functions of y(t) in examples 1and 2 above) reduces to zero because the derivative of a constant (and ordinary number without the t attached to it) is always zero.
One last example,
y(t) = 2t^6 -3t²
V(t) = d(t)/dt = 12t^5 - 6t
Answer:the paper clip will be attracted to the magnet
Explanation:
Answer:
T1 = 490.5 [N], T2 = 490.5[N]
Explanation:
First, we must draw a free body diagram of the steel ball hanging and the two wires holding it as well as the angle forming the wires between them.
The free-body diagram can be seen in the attached image.
As the cables are symmetrical with respect to the vertical axis, the force in cables 1 and 2 is equal, so when performing a force sum equal to zero on the Y-axis, we can find the force value of any cable.
The solution of the equations can be seen in the attached image
12 cm x 2 cm x 3 cm = 72 cm3
