Question

Many gases are shipped in high-pressure containers. Consider a steel tank whose volume is 55.0 gallons and which contains O2 gas at a pressure of 16,500 kPa at 23 degrees C.. . What is the mass of O2 in the tank in g?. . What volume would the gas occupy at STP in liters?. . At what temperature would the pressure in tank equal 1.55 atm?. . What would be the pressure of the gas, in kPA, if it were transferred to a container at 24 degrees C, whose volume is 55.0 L ?

Answer 1

We are given with conditions on temperature, pressure and volume of gas. In this problem, we apply ideal gas law PV = nRT to solve what are asked.

1. PV = nRT ; n = m/MM
    16.5 x10^6 Pa * 0.003785 m3= n * 8.314 Pa m^3/ mol K * (23+273) K 
    n = 25.38 mol; mass = 812.08 grams. 
2. V at STP is 22.4 L/mol
3. PV = nRT = 1.5 atm *  0.003785 *1000 L = 25.38 mol * 0.0821 L atm/mol K * T ; T = 2.72 K
4. P * 55 m3/1000 = 25.38 mol * 8.314 Pa m^3/ mol K * (24+273) K
  P = 1139. 45 kPa