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3 years ago

Carlos uses a rope to pull his car 30 m to a parking lot because it ran out of gas

Physics

1 answer:

hodyreva [135]3 years ago

3 0

Carlos used a rope to pull his car 30m to a parking lot because it ran out of gas.

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A mass of 0.1 kg of helium fills a 0.2 m3 rigid tank at 350 kPa. The vessel is heated until the pressure is 700 kPa. Calculate t

QveST [7]

Explanation:

(a) First, we will calculate the number of moles as follows.

No. of moles = $\frac{\text{mass}}{\text{molar mass}}$

Molar mass of helium is 4 g/mol and mass is given as 0.1 kg or 100 g (as 1 kg = 1000 g).

Putting the given values into the above formula as follows.

No. of moles = $\frac{\text{mass}}{\text{molar mass}}$

= $\frac{\text{100 g}}{4 g/mol}$

= 25 mol

According to the ideal gas equation,

PV = nRT

or, $(P_{2} - P_{1})V = nR (T_{2} - T_{1})$

$(6.90 atm - 3.45 atm) \times 200 L = 25 \times 0.0821 L atm/mol K \Delta T$

$\Delta T$ = 336.17 K

Hence, temperature change will be 336.17 K.

(b) The total amount of heat required for this process will be calculated as follows.

q = $mC \Delta T$

= $100 g \times 5.193 J/g K \times 336.17 K$

= 174573.081 J/K

or, = 174.57 kJ/K (as 1 kJ = 1000 J)

Therefore, the amount of total heat required is 174.57 kJ/K.

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3 years ago

Point P is on the rim of a wheel of radius 2.0 m. At time t = 0, the wheel is at rest, and P is on the x-axis. The wheel undergo

oksian1 [2.3K]

Answer:

e). $a = 0.066 m/s^2$

Explanation:

As we know that wheel is turned by 90 degree angle

so the angular speed of the wheel is given as

$\omega_f^2 - \omega_i^2 = 2\alpha \theta$

now we have

$\omega_f^2 - 0 = 2(0.01)(\frac{\pi}{2})$

$\omega = 0.177 rad/s$

now the centripetal acceleration of the point P is given as

$a_c = \omega^2 R$

$a_c = (0.177)^2(2)$

$a_c = 0.063 m/s^2$

tangential acceleration is given as

$a_t = R\alpha$

$a_t = 2(0.01)$

$a_t = 0.02 m/s^2$

now net acceleration is given as

$a = \sqrt{a_t^2 + a_c^2}$

$a = \sqrt{0.02^2 + 0.063^2}$

$a = 0.066 m/s^2$

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What do all elements in a column in the periodic table have in common?

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