The molar mass of CO2 can be calculated as follows;
CO2 — 12 + (16x2) = 12+ 32 = 44 g
Therefore molar mass of CO2 is 44 g/mol
In 44 g of CO2 there’s 1 mol of CO2
Then 1 g of CO2 there’s 1/44 mol of CO2
Therefore in 78.3 g of CO2 there’s — 1/44 x 78.3 =1.78 mol of CO2
Answer:
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Explanation:
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Name Bromine
Symbol Br
Atomic Number 35
Atomic Mass 79.904 atomic mass units
Number of Protons 35
Number of Neutrons 45
Number of Electrons 35
Melting Point -7.2° C
Boiling Point 58.78° C
Density 3.119 grams per cubic centimeter
Normal Phase Gas
Family Halogens
Period 4
Cost $4.90 per 100 grams
Answer:
a. Rate = k [H2O+-OH][Br-]
Explanation:
For a reaction:
nA+xB→C+D
The rate of the reaction is:
Rate = [A]ⁿ[B]ˣ
Now, in a mechanism, the rate of the reaction depends of the slow step. In the problem:
H2O+-OH + Br-→ HOBr + H2O
And the rate is:
<h3>a. Rate = k [H2O+-OH][Br-]
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