Step-by-step explanation:
Given equation is
2y = 3x + 10
3x - 2y + 10 = 0 .....i)
Any line parallel to line I) is
3x - 2y + k = 0 ......ii)
As the line two passes through the point ( 2 , - 5 ) Now substituting the values
3 * 2 - 2 * ( - 5) + k = 0
6 + 10 + k = 0
16 + k = 0
k = - 16
Now putting the value of k in equation two
3x - 2y + 16 = 0 is the required equation.
Hope it will help :)❤
Answer:
Step-by-step explanation:
<u>Quadratic Function</u>
Standard Form of Quadratic Function
The standard representation of a quadratic function is:
where a,b, and c are constants.
When the zeros of f (x1 and x2) are given, it can be written as:
f(x)=a(x-x1)(x-x2)
Where a is a constant called the leading coefficient.
We are given the two roots of f: x1=-3 and x2=4, thus:
f(x)=a(x+3)(x-4)
We also know that f(5)=8, thus:
f(5)=a(5+3)(5-4)=8
Operating:
a(8)(1)=8
Solving:
a=1
The function is:
f(x)=1(x+3)(x-4)
Operating:
Simplify. Combine like terms
7y - 3y = 4y
-12 + 9 = -3
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4y - 3 = 0
Isolate the y. Note the equal sign. What you do to one side, you do to the other side. Do the opposite of PEMDAS.
4y - 3 (+3) = 0 (+3)
4y = 3
4y/4 = 3/4
y = 3/4
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y = 3/4 is your answer
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hope this helps
What exactly are you asking?
100 cm
1 m is equivalent to 100cm
