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3 years ago

15 POINTS PLEASE HELP! NO GUESSING

2 answers:

7 0

He answer is A. encourage agricultural usage in the watershed

if you want to read it for yourself go to
www.nature.org/ourinitiatives/regions/northamerica/unitedstates/indiana/journeywithnature/watersheds...

hope this helps you!!

swat323 years ago

3 0

A is the correct answer! I did a lesson on it

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3. When two liquids are mixed and a solid

sashaice [31]

Answer:

Explanation:

6 0

2 years ago

If the jet is moving at a speed of 1140 km/h at the lowest point of the loop, determine the minimum radius of the circle so that

AnnZ [28]

To solve this problem we will apply the concepts related to the centripetal Force and the Force given by weight and formulated in Newton's second law. Through the two expressions we can find the radius of curve made in the hand. To calculate the normal force, we will include the concepts of sum of forces to obtain the net force on the body at the top and bottom of the maneuver. The expression for centripetal force acting on the jet is

$F_c = \frac{mv^2}{r}$

According to Newton's second law, the net force acting on the jet is

F = ma

Here,

m = mass

a = acceleration

v = Velocity

r = Radius

PART A ) Equating the above two expression the equation for radius is

$\frac{mv^2}{r} = ma$

$r = \frac{v^2}{a}$

Replacing with our values we have that

$r = \frac{(1140km/hr[\frac{1000m}{1km}\frac{1hour}{3600s}])^2}{7(9.8m/s^2)}$

$r = 1.462*10^3m$

PART B )

- The expression for effective weight of the pilot at the bottom of the circle is

$N = mg +\frac{mv^2}{r}$

$N = (69kg)(9.8m/s^2)+\frac{(69)(1140km/hr[\frac{1000m}{1km}\frac{1hour}{3600s}])^2}{1.462*10^3m}$

$N = 5408.87N$

Note that the normal reaction N is directed upwards and gravitational force mg is directed downwards. At the bottom of the circle, the centripetal force is directed upwards. So the centripetal force is obtained from the gravitational force and the normal reaction.

- The expression for effective weight of the pilot at the top of the circle is

$N = mg -\frac{mv^2}{r}$

$N = (69kg)(9.8m/s^2)-\frac{(69)(1140km/hr[\frac{1000m}{1km}\frac{1hour}{3600s}])^2}{1.462*10^3m}$

$N = 4056.47N$

Note that at the top of the circle the centripetal force is directed downwards. So the centripetal force is obtained from normal reaction and the gravitational force.

4 0

3 years ago

A sound wave from a siren has an intensity of 111.2 W/m2 at a certain point, and a second sound wave from a nearby ambulance has

Kazeer [188]

Answer:

The intensity level of the sound wave due to the ambulance is 153.5 dB.

Explanation:

The intensity level of the sound wave due to the ambulance can be calculated using the following equation:

$\beta = 10log(\frac{I}{I_{0}})$

Where:

I: is the intensity of the sound wave from a siren = 111.2 W/m²

I₀: is the reference intensity = 1.0x10⁻¹² W/m²

$\beta = 10log(\frac{111.2 W/m^{2}}{1.0 \cdot 10^{-12} W/m^{2}}) = 140.5 dB$

Now, since the second sound wave from a nearby ambulance has an intensity level 13 dB we have:

$I_{a} = 13 dB + 140.5 dB = 153.5 dB$

Therefore, the intensity level of the sound wave due to the ambulance is 153.5 dB.

I hope it helps you!

5 0

3 years ago

A vehicle in for repair has a burst upper radiator tank. Technician A says thermostat that was stuck in the open position could

Morgarella [4.7K]

Answer:

Technician B

Explanation:

A thermostat being stuck in an open position allows coolant to constantly circulate through the radiator which will cause a drop in the temperature of the engine. Hence, thermostat being stuck in an open position has nothing to do with burst upper radiator.

On the other hand, a radiator cap controls the pressure within the radiator which needs to be kept constant in order prevent overheating or damage to the radiator itself.

Therefore, technician B is correct.

5 0

3 years ago

Pls answer these questions I beg u!! And use the diagram for answering the questions pls help!! I will make u the BRAINLIEST!!!

MA_775_DIABLO [31]

I think this is the answer:

Matter can change its state because of the pressure and/or the temperature.

3 0

2 years ago