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r-ruslan [8.4K]
3 years ago
13

Daily life examples of pressure of solids on solids?​

Physics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

Explanation:

There's a massive amount, just think of anything everyday. Like a table on the floor, or when your walking around and putting pressure on the floor. When you squeeze something which is solid. Anything like that will do.

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Please answer it due to night you!!!!!<br><br>You will be a the brainlist ​
Luba_88 [7]
1. left N49
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6 0
3 years ago
Whitch group of elaments shares charicteristics whith both nonmetals and metloids
fgiga [73]
Answer metalloids hope this helps
4 0
3 years ago
PLEASE HELP<br> The image characteristics are...
VLD [36.1K]

According to the question, the object is placed at 2F

The ray diagram is shown in the figure attached.

According to the figure:

Object AB is at 2F₁

First, we draw a ray parallel to principal axis.

So, it passes through focus after refraction.

We draw another ray which passes through optical center.

So, the ray will go through without any deviation.

Where both refracted rays meet is point A' and the image formed is A'B'

This image is formed at 2F₂

We can say that:

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  • Image is inverted.
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4 0
3 years ago
An object weighs 15N in air and 13N when completely
anastassius [24]

Answer:

The volume of water displaced = 0.204 m³

Explanation:

<em>From Archimedes' principle,</em>

<em>Upthrust = lost in weight = weight of water displaced.</em>

<em>U = W₁ - W₂..................... Equation 1</em>

<em>Where U = upthrust, W₁ = weight in air, W₂ = weight when completely submerged in water.</em>

<em>Given: W₁ = 15 N, W₂ = 13 N</em>

<em>Substituting these values into equation 1</em>

<em>U = 15 - 13 </em>

<em>U = 2 N</em>

<em>But,</em>

<em>Weight of water displaced = mass of water displaced. × acceleration due to gravity.</em>

<em>Mass of water displaced = weight of water displaced/ acceleration due to gravity.................... Equation 2</em>

Where: acceleration due to gravity = 9.8 m/s², weight of water displaced = 2 N

Substituting these values into equation 2

Mass of water displaced = 2/9.8

Mass of water displaced = 0.204 kg.

Also,

Volume of water displaced = mass of water displaced/ Density of water.............. Equation 3

Where Density of water = 1.0 kg/m³, mass of water displaced = 0.204 kg

Substituting these values into equation 3 above,

Volume of water displaced = 0.204/1

volume of water displaced = 0.204 m³

Therefore the volume of water displaced = 0.204 m³

<em />

8 0
3 years ago
Vector A has magnitude of 15.0 m/s and is 75° counter-clockwise up from the x-axis. What are the x- and y-components of the vect
LiRa [457]

Answer:

x component 3.88 y- component 14.488

Explanation:

We have given a vector A which has a magnitude of 15 m/sec which is at 75° counter-clock wise ( anti-clock wise) from x -axis which is clearly shown in bellow figure

Now x-component will be 15 cos75°=3.8822 ( as it makes an angle of 75° with x-axis )

y- component will be 15 sin 75°=14.488

For verification the resultant of x and y component should be equal to 15

So resultant =\sqrt{14.488^2+3.88^2}=15

3 0
3 years ago
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