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EleoNora [17]
3 years ago
12

If 1 inch = 2.54 centimeters, how many inches are there in 2,540 centimeters?

Physics
2 answers:
NARA [144]3 years ago
5 0
1,000 inches would be the answer
denis23 [38]3 years ago
3 0

Answer:

1000 inches

Explanation:

2540/2.54 = 1000

Hope this helps :)

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Central maximum = d* wavelength/ D
thus
12*10-^3 = 3.4*6.32*10-^7/D
D = 3.4*6.32*10-^7/12*10-^3
D = 1.79*10-^4 m
3 0
3 years ago
Henry was giving the school toy for his birthday he can use it to tell how fast someone is moving at the moment in time the toy
pochemuha

Answer:

The toy must calculate the person's speed/velocity

Explanation:

Since the school toy given to Henry can be used to tell how fast someone is moving, the toy must be able to calculate the person's speed/velocity using the <u>average distance</u> covered by the person divided by <u>time taken</u> to cover the distance; average distance ÷ time taken.

The toy must be able to determine the parameters (average distance and time taken) in order to be able to calculate the person's speed/velocity

5 0
3 years ago
List three measurements with different units this are equal to 5 meters
olganol [36]
5kg
50cm
500in
Hope this helped good luck to you
6 0
3 years ago
An occupant of a car can survive a crash if the deceleration during the crash is less than 30 g. Calculate the force on a 64 kg
forsale [732]
The force on a 64 k person decelerating on that rate would be : 

F = ma

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= 18816 N

Hope this helps
6 0
4 years ago
A concert loudspeaker suspended high off the ground emits 31 W of sound power. A small microphone with a 1.0 cm^2 area is 42 m f
Aleonysh [2.5K]

Answer:

intensity of sound at level of microphone is 0.00139 W / m 2

sound intensity level at position of micro phone is 91.456 dB

EXPLANATION:

Given data:

power of sound   P = 31 W

distance betwen microphone & speaker is   42 m

a) intensity of sound at microphone is calculated as

                   I = \frac{P}{A}

                   = \frac{34}{4 \pi ( 44m )^ 2}

                   =  0.00139 W / m 2        

b) sound intensity level at position of micro phone is

                \beta = 10 log \frac{I}{I_o}

    where I_o id reference sound intensity and taken as

                = 1 * 10^{-12} W / m 2  

               \beta = 10 log\frac{0.00139}{10^[-12}}

                     = 91.456 dB

7 0
3 years ago
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