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o-na [289]
3 years ago
15

Observe a seguir os níveis de organização de um ser vivo e marque a alternativa que contém os termos que substituem adequadament

e os números 1, 2 e 3. *
1 ponto



a) 1- tecido, 2- organismo, 3- corpo.

b) 1- órgão, 2- tecido, 3- organismo.

c) 1- tecido, 2- órgão, 3- organismo.

d) 1- organela, 2- tecido, 3- corpo.

​
Physics
2 answers:
SSSSS [86.1K]3 years ago
6 0

Answer:

it will be answer c

Explanation:

svetoff [14.1K]3 years ago
3 0

Answer:

im not spanish but Yuhhh

Explanation:

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Which graph represents the relationship between the magnitude of the gravitational force exerted by earth on a spacecraft the di
Neko [114]

Answer:

B as distance increase force decrease, but it is not a linear relationship.

8 0
3 years ago
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tester [92]
Great question the answer is -25x.
3 0
3 years ago
A 1.8 kg uniform rod with a length of 90 cm is attached at one end to a frictionless pivot. It is free to rotate about the pivot
Leokris [45]

Answer:

a. 32.67 rad/s²  b. 29.4 m/s²

Explanation:

a. The initial angular acceleration of the rod

Since torque τ = Iα = WL (since the weight of the rod W is the only force acting on the rod , so it gives it a torque, τ at distance L from the pivot )where I = rotational inertia of uniform rod about pivot = mL²/3 (moment of inertia about an axis through one end of the rod), α = initial angular acceleration, W = weight of rod = mg where m = mass of rod = 1.8 kg and g = acceleration due to gravity = 9.8 m/s² and L = length of rod = 90 cm = 0.9 m.

So, Iα = WL

mL²α/3 = mgL

dividing through by mL, we have

Lα/3 = g

multiplying both sides by 3, we have

Lα = 3g

dividing both sides by L, we have

α = 3g/L

Substituting the values of the variables, we have

α = 3g/L

= 3 × 9.8 m/s²/0.9 m

= 29.4/0.9 rad/s²

= 32.67 rad/s²

b. The initial linear acceleration of the right end of the rod?

The linear acceleration at the initial point is tangential, so a = Lα = 0.9 m × 32.67 rad/s² = 29.4 m/s²

5 0
3 years ago
The ballistic pendulum is a device used to measure the speed of a projectile such as a bullet. The projectile of mass m is fired
My name is Ann [436]

Answer:

Relation between initial speed of bullet and height h is given as

v = \frac{m + M}{m}\sqrt{2gh}

Explanation:

As we know that system of block and bullet swings up to height h after collision

So we have

(m + M)gh = \frac{1}{2}(m + M)v_1^2

so we have

v_1 = \sqrt{2gh}

so speed of the block + bullet just after the impact is given by above equation

Now we also know that there is no force on the system of bullet + block in the direction of motion

So we can use momentum conservation

mv = (m + M)v_1

now we have

v = \frac{m + M}{m}\sqrt{2gh}

5 0
3 years ago
How large a force is necessary to stretch a 4.0-mm-diameter steel wire from its original length by 1.0%?
jekas [21]

The force needed to stretch the steel wire by 1% is 25,140 N.

The given parameters include;

  • diameter of the steel, d = 4 mm
  • the radius of the wire, r = 2mm = 0.002 m
  • original length of the wire, L₁
  • final length of the wire, L₂ = 1.01 x L₁ (increase of 1% = 101%)
  • extension of the wire e = L₂ - L₁ = 1.01L₁ - L₁ = 0.01L₁
  • the Youngs modulus of steel, E = 200 Gpa

The area of the steel wire is calculated as follows;

A = \pi r^2\\\\ A= 3.142 \times (0.002)^2\\\\ A= 1.257 \times 10^{-5} \ m^2

The force needed to stretch the wire is calculated from Youngs modulus of elasticity given as;

E = \frac{stress}{strain} = \frac{F/A}{e/L} = \frac{FL}{Ae} \\\\F = \frac{EAe}{L}

F = \frac{200 \times 10^9\  \times\  1.257\times 10^{-5}\  \times \ 0.01l_1}{l_1} \\\\F = 25,140\ N

Thus, the force needed to stretch the steel wire by 1% is 25,140 N.

Learn more here: brainly.com/question/21413915

4 0
2 years ago
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