Answer:
Artificial weight = 70.27 N = 15.80 lbs
Explanation:
The earth weight of the astronaut = 160 lbs = 711.72 N
The weight on earth = m × g(earth)
g(earth) = 9.8 m/s²
711.72 = m × 9.8
m = (711.72/9.8)
m = 72.62 kg
But at the space station, the space station rotates once every 70 s to create an artificial radial acceleration that creates a radial gravity pulling the objects on the space station towards the centre of that space station.
radial acceleration = α = (v²/r)
v = rw,
α = (rw)²/r
α = rw²
r = radius of rotation = 120 m
w = angular velocity = (2π/70) (it completes 1 rotation, 2π radians, in 70 s)
w = 0.0898 rad/s
α = 120 × (0.0898²)
α = 0.968 m/s²
Artificial weight = (mass of astronaut) × (Radial acceleration) = 72.62 × 0.968
Artificial weight = 70.27 N = 15.80 lbs
Hope this Helps!!!
Calculate the pressure due to sea water as density*depth.
That is,
pressure = (1025 kg/m^3)*((9400 m)*(9.8 m/s^2) = 94423000 Pa = 94423 kPa
Atmospheric pressure is 101.3 kPa
Total pressure is 94423 + 101.3 = 94524 kPa (approx)
The area of the window is π(0.44 m)^2 = 0.6082 m^2
The force on the window is
(94524 kPa)*(0.6082 m^2) = 57489.7 kN = 57.5 MN approx
When water vaporizes into the air, it becomes humid out.
Amount of time the two substances are in contact. area in contact between the two substances. amount of heat needed to raise the temperature one degree Celsiusof the material that makes up the substances. density of the two substances in contact.J