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Sholpan [36]
3 years ago
7

Snow in New York City weathers gargoyles on buildings by which process?

Chemistry
1 answer:
IgorC [24]3 years ago
5 0

Answer: Acid Precipitation

Explanation:

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How are isotopes of the same chemical element alike? How are they different?
Stella [2.4K]

<u>Answer:</u> The atomic mass of these species is different and atomic number remains same.

<u>Explanation:</u>

Isotopes are the chemical species of the same element having different number of neutrons.

  • Atomic number is equal to the number of protons or electrons present in that element.

Atomic Number = Number of electrons = Number of protons

  • Atomic mass is defined as the sum of number of protons and neutrons contained in an atom.

Atomic Mass = Number of protons + Number of neutrons

For isotopes, as the number of neutrons differ, the atomic mass also differs.

For Example: Carbon has 3 naturally occurring isotopes: _6^{12}\textrm{C},_6^{13}\textrm{C}\text{ and }_6^{14}\textrm{C}. The atomic number remains the same but atomic mass differs.

Hence, for isotopes, the atomic mass of these species is different and atomic number remains same.

6 0
3 years ago
Atoms of the same element can have different properties.<br><br> True<br> False
Pavel [41]
I think the answer is true if so i hope it helps

5 0
3 years ago
Read 2 more answers
7m-11=10 como se acomoda pls ayuda​
Reptile [31]

Answer:

3

Explanation:

7m-11=10

quitar 11 de ambos lados

7m -11+11 = 10+11

7m=21

7/7m=21/7

m=3

3 0
3 years ago
Read 2 more answers
What is the volume, in mL, of 0.50 moles of ammonia (NH3) at STP?
blagie [28]
For the purpose we will here use the ideal gas law:

p×V=n×R×T

V= ?
n = 0.5 moleT= 273.15 K (at STP)
p= 101.325 kPa (at STP)
R is  universal gas constant, and its value is 8.314 J/mol×K

Now when we have all necessary date we can calculate the number of moles:
V=nxRxT/p
V=0.5x8.314x273.15/101.325= 11.2 L = 11200 mL

Answer: D.
5 0
3 years ago
In a 100 g sample of iron(III) oxide, how many grams of iron are present?
e-lub [12.9K]
The formula of Iron(III) oxide is Fe2O3
In order to calculate the mass of iron in a given sample of iron(III) oxide, we must first know the mass percentage of iron in iron(III) oxide. This is calculated by:
[mass of iron in one mole of iron(III) oxide/ mass of one mole of iron(III) oxide] * 100 
= [(moles of iron * Mr of iron) / (moles of Iron * Mr of Iron + moles of Oxygen * Mr of Oxygen)] * 100
= [(2 * 56) / (2 * 56 + 3 * 16)] * 100
= (112 / 160) * 100
= 70%
Thus, in a 100g sample, the weight of iron will be:
100 * 70%
= 70 grams
8 0
4 years ago
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