In the reaction between 1 molecule of bromine and 2 molecules of potassium chloride, there are six atoms in the products.
Let's consider the balanced equation for the reaction between 1 molecule of bromine and 2 molecules of potassium chloride. This is a single replacement reaction.
Br₂ + 2 KCl ⇒ 2 KBr + Cl₂
We obtain as products, 2 molecules of potassium bromide and 1 molecule of chlorine.
- 1 molecule of KBr has 2 atoms, so 2 molecules contribute with 4 atoms.
- 1 molecule of Cl₂ has 2 atoms.
- The 4 atoms from KBr and the 2 atoms from Cl₂ make a total of 6 atoms.
In the reaction between 1 molecule of bromine and 2 molecules of potassium chloride, there are six atoms in the products.
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Answer:
To calculate the atomic mass of a single atom of an element, add up the mass of protons and neutrons. Example: Find the atomic mass of an isotope of carbon that has 7 neutrons. You can see from the periodic table that carbon has an atomic number of 6, which is its number of protons.
Explanation:
Answer:
Newton’s third law of motion states that every action has an equal and opposite reaction. This indicates that forces always act in pairs. Reaction forces are equal and opposite, but they are not balanced forces because they act on different objects so they don’t cancel each other out.
The magnitude of work done by the gas is 279 J and the sign is negative so W = -279 J as work is done by the system.
<u>Explanation:</u>
According to first law of thermodynamics, the change in internal energy of the system is equal to the sum of the heat energy added or released from the system with the work done on or by the system. If the heat energy is added to the system to perform a certain work, then the heat energy is taken as positive, while it will be negative when the heat energy is released from the system.
Similarly, in this case, the heat energy of 597 J is added to the system. So the heat energy will be positive, while the gas expansion occurs means work is done by the system.
ΔU = Q+W
Since ΔU is the change in internal energy which is given as 318 J and the heat energy added to the system is Q = 597 J.
Then the work done by the gas = ΔU - Q = 318 J - 597 J = - 279 J.
As the work is done by the system, so it will be denoted in negative sign and the magnitude of work done by the gas is 279 J.
