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xeze [42]
3 years ago
13

A 2-ft-thick block constructed of wood (sg = 0.6) is submerged in oil (sg = 0.8), and has a 2-ft-thick aluminum (specific weight

= 168 lb/ft3) plate attached to the bottom as indicated in fig. p2.146. (a) determine completely the force required to hold the block in the position shown. (b) loca

Physics
1 answer:
solong [7]3 years ago
6 0
Refer to the figure shown below.

Assume that
g = 32 ft/s², acceleration due to gravity
ρ = 62.4 lb/ft³, density of water
A = 1 ft², the surface area of each of the blocks.

Calculate the weight of the wooden block (sg = 0.6).
W₁ = (0.6*62.4 lb/ft³)*(2 ft³) = 74.88 lb
Calculare the weight of the aluminum block (sg = 0.8)
W₂ = (0.8*62.4)*(2) = 99.84 lb

Use the Archimedes Principle to calculate buoyant forces.
For the wooden block,
B₁ = (62.4 lb/ft²)*(2 ft³) = 124.8 lb
Also, for the aluminum block,
B₂ = 124.8 lb

Let F = the force required to hold the blocks in position. Then
-F + B₁ + B₂ = W₁ + W₂
-F + 249.6 = 174.72
F = 74.88 lb

The answer for Part (a):   
74.88 lb, acting downward.

Forces W₁, B₁ act at the center of mass of the wooden block, and W₂, B₂ act at the center of mass of the aluminum block.
Let x =  the location of the overall force on the two blocks, measured downward from the top of the wooden block, as shown in the figure.
Then
(W₁ - B₁)*(1.0) + (W₂ - B₂)*(3.0) = (W₁+W₂-B₁-B₂)*x
-49.92 + (-24.96)*(3) = -74.88x
-124.8 = -74.88x
x = 1.668 ft

The answer for part (b): 
The resultant force should be applied at 1.67 ft below the top of the wooden block.

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IgorC [24]

Answer:

41.667 per cent of the total kinetic energy is translational kinetic energy.

Explanation:

As the spherical shell is rolling without slipping at constant speed, the system can be considered as conservative due to the absence of non-conservative forces (i.e. drag, friction) and energy equation can be expressed only by the Principle of Energy Conservation, whose total energy is equal to the sum of rotational and translational kinetic energies. That is to say:

E = K_{t} + K_{r}

Where:

E - Total energy, measured in joules.

K_{r} - Rotational kinetic energy, measured in joules.

K_{t} - Translational kinetic energy, measured in joules.

The spherical shell can be considered as a rigid body, since there is no information of any deformation due to the motion. Then, rotational and translational components of kinetic energy are described by the following equations:

Rotational kinetic energy

K_{r} = \frac{1}{2}\cdot I_{g}\cdot \omega^{2}

Translational kinetic energy

K_{t} = \frac{1}{2}\cdot m \cdot R^{2}\cdot \omega^{2}

Where:

I_{g} - Moment of inertia of the spherical shell with respect to its center of mass, measured in kg\cdot m^{2}.

\omega - Angular speed of the spherical shell, measured in radians per second.

R - Radius of the spherical shell, measured in meters.

After replacing each component and simplifying algebraically, the total energy of the spherical shell is equal to:

E = \frac{1}{2}\cdot (I_{g} + m\cdot R^{2})\cdot \omega^{2}

In addition, the moment of inertia of a spherical shell is equal to:

I_{g} = \frac{2}{3}\cdot m\cdot R^{2}

Then, total energy is reduced to this expression:

E = \frac{5}{6}\cdot m \cdot R^{2}\cdot \omega^{2}

The fraction of the total kinetic energy that is translational in percentage is given by the following expression:

\%K_{t} = \frac{K_{t}}{E}\times 100\,\%

\%K_{t} = \frac{\frac{1}{2}\cdot m \cdot R^{2}\cdot \omega^{2} }{\frac{5}{6}\cdot m \cdot R^{2}\cdot \omega^{2} } \times 100\,\%

\%K_{t} = \frac{5}{12}\times 100\,\%

\%K_{t} = 41.667\,\%

41.667 per cent of the total kinetic energy is translational kinetic energy.

7 0
4 years ago
What would happen if a solid temperature increases
Ber [7]
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3 years ago
The speed of sound in air is around 330 m/s. If a bat emits a single high-pitched ‘click’ of sound in a cave that is 25m wide, c
Bingel [31]

Answer:

0.15 s

Explanation:

From the question given above, the following data were obtained:

Speed of sound (v) = 330 m/s

Distance (x) = 25 m

Time (t) =?

The time taken for the echo of the sound to the bat can be obtained as follow:

v = 2x / t

330 = 2 × 25 / t

330 = 50 / t

Cross multiply

330 × t = 50

Divide both side by 330

t = 50 / 330

t = 0.15 s

Thus, it will take 0.15 s for the echo of the sound to the bat

4 0
3 years ago
Find the radioactivity of a 1 g sample of 226Ra given that <img src="https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D1620" id="TexFormul
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Answer:

Explanation:

No of atoms of Ra in 1 g of sample = 6.023 x 10²³ / 226

N = 2.66 x 10²¹

disintegration constant λ = .693 / half life

half life = 1620 x 365 x 60 x 60 x 24 = 5.1 x 10¹⁰ s

disintegration constant λ = .693 / 5.1 x 10¹⁰

radioactivity dn / dt = λN

= (.693 / 5.1 x 10¹⁰ )  x 2.66 x 10²¹

= .3614 x 10¹¹ per sec

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What two factors affect the rate of acceleration in an object
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