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2 years ago

The rate an object is moving relative to a reference point is its

Physics

1 answer:

natulia [17]2 years ago

5 0

Velocity is an object's rate of change (usually over time) of its displacement.

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How is volume and temperature related?

ololo11 [35]

Charles' Law: The Temperature-Volume Law. This law states that the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature. As the volume goes up, the temperature also goes up, and vice-versa.

5 0

2 years ago

what is the acceleration of each body of mass 5kg rests on a frictionless table and is connected to a cable that passes over a p

Oksanka [162]

Answer:

6.53 m/s²

Explanation:

Let m₁ = 5 kg and m₂ = 10 kg. The figure is attached and free body diagrams of the objects are also attached.

Both objects (m₁ and m₂) have the same magnitude of acceleration(a). Let g be the acceleration due to gravity = 9.8 m/s². Hence:

T = m₁a (1)

m₂g - T = m₂a (2)

substituting T = m₁a in equation 2:

m₂g - m₁a = m₂a

m₂a + m₁a = m₂g

a(m₁ + m₂) = m₂g

a = m₂g / (m₁ + m₂)

a = (10 kg * 9.8 m/s²) / (10 kg + 5 kg) = 6.53 m/s²

Both objects have an acceleration of 6.53 m/s²

8 0

2 years ago

The basic methods and techniques used by psychologists to investigate human behavior?

Stels [109]

Telepathy duhh like when SpongeBob stared at Patrick he know they where thinking the same thing or maybe that was because they are both idiots i dont know <span />

6 0

2 years ago

What is the mass of an object that creates 33,750 joules of energy by traveling at 30 m/sec?

nikklg [1K]

The Energy is Kinetic Energy.

Kinetic Energy = 1/2*mv², Where m is mass in kg, v is velocity in m/s

Energy is 33750 Juoles, v = 30m/s

1/2*mv² = E

1/2*m*30² = 33750

m = (2*33750) / (30²) Using a calculator

m = 75 kg

Mass of object is 75 kg.

5 0

3 years ago

Read 2 more answers

A person's prescription for her new bifocal glasses calls for a refractive power of -0.450 diopters in the distance-vision part,

Angelina_Jolie [31]

Answer:

Far point of the eye is 22.24 m

Far point of the eye is 0.4 m

Explanation:

$\frac{1}{f}=-0.045$

Object distance = u

Image distance = v

Lens equation

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=-0.045-\frac{1}{\infty}\\\Rightarrow \frac{1}{v}=\frac{1}{-0.045}\\\Rightarrow v=-22.22\ m$

Far point

$|v|+\text{Position from eye}\\ =|-22.22|+0.02\\ =22.24\ m$

Far point of the eye is 22.24 m

Object distance = u = 0.25-0.02 = 0.23 m

$\frac{1}{f}=1.75$

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=1.75-\frac{1}{0.23}\\\Rightarrow v=-0.38\ m$

Near point

$|v|+\text{Position from eye}\\= |-0.38|+0.02\\ =0.4\ m$

Far point of the eye is 0.4 m

7 0

2 years ago