In the following reaction: Ca+2 + 2Br- ---> BaBr2, which of the reactants is LEO and which is GER?

scZoUnD [109]

The quality or state of being volcanic.

3 0

3 years ago

Juanita dissolves 46 g of MgBr2 (molar mass: 184.11 g/mol) in 0.5 kg of distilled water. What is the molality of the solution?

irina [24]

Formula: molality, m = n solute / kg solvent

n solute = # of moles of solute = mass(g) / molar mass

Molar mass of Mg Br2 = 184.11 g/mol

m = [46g / 184.11 g/mol] / 0.5 kg = 0.50 mol/kg

3 0

3 years ago

Write a short explanation for the ozone hole

SVEN [57.7K]

Answer:

A severe depletion of ozone in a region of the ozone layer, particularly over Antarctica and over the Arctic. The depletion is caused by the destruction of ozone by CFCs and by other compounds, such as carbon tetrachloride (CCl4) and carbon tetrafluoride (CF4).

Explanation:

A severe depletion of ozone in a region of the ozone layer, particularly over Antarctica and over the Arctic. The depletion is caused by the destruction of ozone by CFCs and by other compounds, such as carbon tetrachloride (CCl4) and carbon tetrafluoride (CF4).

3 0

3 years ago

Pls help<br> 25 points, thank you

denis23 [38]

Answer:

how to help people that helps

7 0

3 years ago

4) 10.00 mL of sulfuric acid is neutralized in a titration using 18.54 mL of 0.100 M NaOH.

sdas [7]

Answer:

a) $H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

b) $M_{H_2SO_4}=0.0927M$

Explanation:

Hello!

In this case, for this acid-base reaction which also known as a neutralization because sulfuric acid is neutralized with sodium hydroxide, we can write the undergoing chemical reaction as shown below:

$H_2SO_4+NaOH\rightarrow Na_2SO_4+H_2O$

However, it needs to be balanced as two sodium atoms are yielded:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

Next, since there is a 1:2 mole ratio between the acid and the base, at the equivalence point, at which the moles of acid and base are consumed, we write:

$2n_{H_2SO_4}=n_{NaOH}$

Which can also be written in terms of the given volumes and concentration of the base:

$2M_{H_2SO_4}V_{H_2SO_4}=M_{NaOH}V_{NaOH}$

In such a way, we solve for the concentration of sulfuric acid as shown below:

$M_{H_2SO_4}=\frac{M_{NaOH}V_{NaOH}}{2V_{H_2SO_4}} =\frac{18.54mL*0.100M}{2*10.00mL}\\\\ M_{H_2SO_4}=0.0927M$

Best regards!

5 0

3 years ago