From equations of motion,
v^2 = u^2 + 2as ----- v = final velocity, u = initial velocity, a = acceleration, s = distance covered.
Using the vales given;
v^2 = 15^2 + 2*4*50 = 625
v = Sqrt (625) = 25 m/s
Answer:
F = 100 N
Explanation:
The torque is given by the expression
τ = F x r
where bold letters indicate vectors, the magnitude of this expression is
τ = F r sin θ
In general, when tightening a nut, the force is applied perpendicular to the arm, therefore θ = 90 and sin 90 = 1
τ = F r
F = τ / r
calculate
F = 30 / 0.30
F = 100 N
The resultant vector is 5.2 cm at a direction of 12⁰ west of north.
<h3>
Resultant of the two vectors</h3>
The resultant of the two vectors is calculated as follows;
R = a² + b² - 2ab cos(θ)
where;
- θ is the angle between the two vectors = 45° + (90 - 57) = 78⁰
- a is the first vector
- b is the second vector
R² = (3.7)² + (4.5)² - (2 x 3.7 x 4.5) cos(78)
R² = 27.02
R = 5.2 cm
<h3>Direction of the vector</h3>
θ = 90 - 78⁰
θ = 12⁰
Thus, the resultant vector is 5.2 cm at a direction of 12⁰ west of north.
Learn more about resultant vector here: brainly.com/question/28047791
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