Pretty sure it hit some rocks and landed on Mars
Answer:
Apply this to waves: count the number of waves passing each second (= frequency), and multiply by the length of each (= wavelength) to find the speed. speed = distance/time = l/T= l / (1/f) = f λ. Work through three examples: A simple example, perhaps for sound in air, with values in Hz and m.
Explanation:Apply this to waves: count the number of waves passing each second (= frequency), and multiply by the length of each (= wavelength) to find the speed. speed = distance/time = l/T= l / (1/f) = f λ. Work through three examples: A simple example, perhaps for sound in air, with values in Hz and m.
Amplitude is the fluctuation or displacement of a wave from its mean value. With sound waves, it is the extent to which air particles are displaced, and this amplitude of sound or sound amplitude is experienced as the loudness of sound
But it seems that in some circumstances, sound can jump between objects in a vacuum after all. Sound waves are travelling vibrations of particles in media such as air, water or metal. So it stands to reason that they cannot travel through empty space, where there are no atoms or molecules to vibrate.
Answer:
1) 
2) a. 
b. 
c. 
Explanation:
1)
- given initial length,
- initial temperature,
- final temperature,
- coefficient of linear expansion,
<u>∴Change in temperature:</u>
We have the equation for change in length as:
2)
Given relation:
where:
= change in volume
V= initial volume
=change in temperature
- initial volume of tank,
- initial volume of gasoline,
- initial temperature of steel tank,
- initial temperature of gasoline,
- coefficients of volumetric expansion for gasoline,
- coefficients of volumetric expansion for gasoline,
a)
final temperature of gasoline, 
∴Change in temperature of gasoline,
Now,
b)
final temperature of tank, 
∴Change in temperature of tank,
Now,
c)
Quantity of gasoline spilled after the given temperature change:
Answer:
Velocity = 0.47 m/s
Direction = 65 degrees South of east.
(295 degrees counter clockwise from + X axis).
Explanation:
Conservation of momentum along the X and Y directions can be used to determine the velocity of the 4 kg puck.
Along the X direction momentum conservation is as follows:
2.5 cos 20 + 4.0 cos 90 = 2.5 cos 30 + 4 v cos α
⇒ v cos α = 2.5 ( cos 20 - cos 30) ÷ 4 = 0.46 m/s
2.5 sin 20 + 4 sin 90 = 2.5 sin 30 + 4 v sin α
v sin α = (2.5 sin 20 - 2.5 sin 30) ÷ 4 = -0.0987 m/s
v = √(v² cos² α + v² sin² α) = √ (0.46² + (-0.0987)² = 0.47 m/s
Direction = α = tan⁻¹ (-0.0987/0.46) = -65 degrees = 65 degrees clock wise from +X axis or 295 degrees counter clockwise from +X axis
