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cestrela7 [59]
3 years ago
9

In the process of electricity, what flows through the wires?

Physics
2 answers:
OLEGan [10]3 years ago
8 0
The answer is electrons
dusya [7]3 years ago
4 0
I think your answer is C.
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According to Newton's first law, an object at rest will _____.
Vesnalui [34]
Stay at rest unless moved my force! :)
8 0
3 years ago
Someone help please by providing work and answers please :)
cupoosta [38]
There are two ways to solve this. The longer way is to use those equations to calculate numbers for total distance.

The easier way is to find the area under the graph. That's right, AREA UNDER VELOCITY-TIME graph is the TOTAL DISTANCE travelled!

it's a shortcut.

Let's split up the area into a triangle and rectangle:

Triangle = 0.5(4-0)(10-0) = 20 m
Rectangle = (6-4)(10-0) = 20 m

Total distance = 40 m!
6 0
3 years ago
A child uses a rubber band to launch a bottle cap at an angle of 37.0° above the horizontal. The cap travels a horizontal distan
zavuch27 [327]

Answer:

Initial velocity will be 1.356 m/sec      

Explanation:

Let the initial speed = u

Angle at which rubber band is launched = 37°

Horizontal component of initial velocity u_x=ucos\Theta =ucos37^{\circ}=0.7986u

Time is given as t = 1.20 sec

Distance in horizontal direction = 1.30 m

We know that distance = speed × time

So time t=\frac{distance}{speed}

1.20=\frac{1.3}{0.7986u}

u=1.356m/sec

So initial velocity will be 1.356 m/sec

3 0
3 years ago
A rubber ball of mass 18.5 g is dropped from a height of 1.90 m onto a floor. The velocity of the ball is reversed by the collis
kati45 [8]

Answer:

J=0.211kg.m/s

Explanation:

The impulse-momentum theorem states:

J=\Delta p\\J=m(v_a-v-b)\\where:\\m=mass\\v_a=velocity\_after\\v_b=velocity\_before

The velocity before the impact is given by:

(v_b)^2=2.a.\Delta y\\v_b=\sqrt{2*(9.8m/s^2)1.90m}=6.10m/s(-\hat{j})

For the velocity after the impact:

(v_f)^2=(v_a)^2+2.a.\Delta y\\(0)^2=(v_a)^2+2.(-9.8m/s^s).(1.45m)\\\\v_a=\sqrt{2*9.8m/s^2*1.45m}\\v_a=5.33m/s(\hat{j})

so:

J=18.5*10^{-3}kg(5.33m/s(\hat{j})-6.10m/s(-\hat{j}))\\\\J=18.5*10^{-3}kg(5.33m/s(\hat{j})+6.10m/s(\hat{j}))\\\\J=0.211kg.m/s

3 0
3 years ago
Which phase of cell division is shown?
timurjin [86]

Answer:

B

This is prophase as the nucleus disappears. Anaphase is when the chromosomes separate. Telophase is when the cell is about the divide.

5 0
3 years ago
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