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Jlenok [28]
2 years ago
6

The equilibrium constant for the reaction: HCHO(g) ⇌ H2(g) + CO(g).

Chemistry
1 answer:
tiny-mole [99]2 years ago
3 0

Answer:

K = [H2] [CO] / [HCHO]

Explanation:

HCHO(g) ⇌ H2(g) + CO(g)

We can obtain the expression for the equilibrium constant for the above equation as follow:

Equilibrium constant, K for a given reaction is the ratio of the concentration of the product raised to their coefficient to the concentration of the reactant raised to their coefficient.

Thus, the equilibrium constant, K for the above equation can be written as follow:

K = [H2] [CO] / [HCHO]

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I’m assuming your just writing the formula? If so
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2 years ago
3.
Alecsey [184]

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<h3>no it is not allowed</h3>

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<h3>Liwis structure shows the elements symbol with dots thet represents valance electrons ; in second row elements their atomic number is 3 up to 10 , from Li up to Ne from their electron configuration their valance electron will be from 1 up to 8 respectivelly ,if lewis structure represents the element with it is symbol and dots that represents valance electron the second row elements cannot have more than an octet of valance electrons surrounding it.</h3>

<h3>I think it is help ful for you </h3>
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2 years ago
On the periodic table, calcium is in group 2. What is true about calcium?
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Answer:

Explanation:

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7 0
2 years ago
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