The equilibrium constant for the reaction: HCHO(g) ⇌ H2(g) + CO(g).

Chemistry

1 answer:

tiny-mole [99]3 years ago

3 0

Answer:

K = [H2] [CO] / [HCHO]

Explanation:

HCHO(g) ⇌ H2(g) + CO(g)

We can obtain the expression for the equilibrium constant for the above equation as follow:

Equilibrium constant, K for a given reaction is the ratio of the concentration of the product raised to their coefficient to the concentration of the reactant raised to their coefficient.

Thus, the equilibrium constant, K for the above equation can be written as follow:

K = [H2] [CO] / [HCHO]

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<span>5.5×10−2M in calcium chloride and 8.0×10−2M in magnesium nitrate.
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Proportion: 2 mol PO4(3-) / 3 mol Ca(2+) = x / 0.0825 mol Ca(2+)

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=> 2 mol PO4(3-) / 3 mol Mg(2+) = x / 0.12 mol Mg(2+)

=> x = 0.12 * 2/3 mol PO4(3-) = 0.16 mol PO4(3-)

5) Total number of moles of PO4(3-)

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=> 1 mol Na3PO4 : 1 mol PO4(3-)

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mass in grams = number of moles * molar mass

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