All categories

3 years ago

The equilibrium constant for the reaction: HCHO(g) ⇌ H2(g) + CO(g).

Chemistry

1 answer:

tiny-mole [99]3 years ago

3 0

Answer:

K = [H2] [CO] / [HCHO]

Explanation:

HCHO(g) ⇌ H2(g) + CO(g)

We can obtain the expression for the equilibrium constant for the above equation as follow:

Equilibrium constant, K for a given reaction is the ratio of the concentration of the product raised to their coefficient to the concentration of the reactant raised to their coefficient.

Thus, the equilibrium constant, K for the above equation can be written as follow:

K = [H2] [CO] / [HCHO]

You might be interested in

Two substances both exhibit hydrogen bonding. Substance A has a boiling point of 78.4ºC. Substance B has a boiling point of 100º

Feliz [49]

Answer:

The answer is C

Explanation:

Just took the test

6 0

2 years ago

The scattering of a stream of positively charged particles when striking a thin film of gold confirms that the positive charge i

GenaCL600 [577]

Answer:

According to Thompson's model, Every atom consists of a positively charged sphere of radius 10-- 10m in which entire mass and positive charge of the atom are uniformly distributed inside the sphere electrons are embedded like seeds in watermelon. According Rutherford entire poistive charge and mass of the atom are concentrated in a tiny central core of the atom which is called atomic nucleus contains. Size of nucleus = 10-- 15m. The nucleus contains protons and neutrons. Negatively charged electrons revolve around the nucleus in circular orbits.

Explanation:

8 0

3 years ago

Read 2 more answers

How many liters of 0.615 M NaOH will be needed to raise the pH of 0.385 L of 5.13 M sulfurous acid (H2SO3) to a pH of 6.247?

givi [52]

Answer:

Volume of NaOH required = 3.61 L

Explanation:

H2SO3 is a diprotic acid i.e. it will have two dissociation constants given as follows:

$H2SO3\leftrightarrow H^{+}+HSO3^{-}$ --------(1)

where, Ka1 = 1.5 x 10–2 or pKa1 = 1.824

$HSO3^{-}\leftrightarrow H^{+}+SO3^{2-}$ --------(2)

where, Ka2 = 1.0 x 10–7 or pKa2 = 7.000

The required pH = 6.247 which is beyond the first equivalence point but within the second equivalence point.

Step 1:

Based on equation(1), at the first eq point:

moles of H2SO3 = moles of NaOH

$i.e. \ 5.13\ moles/L*0.385L = moles\ NaOH\\therefore, \ moles\ NaOH = 1.98\ moles\\V(NaOH)\ required = \frac{1.98\ moles}{0.615\ moles/L} =3.22L$

Step 2:

For the second equivalence point setup an ICE table:

$HSO3^{-}+OH^{-}\leftrightarrow H2O+SO3^{2-}$

Initial 1.98 ? 0

Change -x -x x

Equil 1.98-x ?-x x

Here, ?-x =0 i.e. amount of OH- = x

Based on the Henderson buffer equation:

$pH = pKa2 + log\frac{[SO3]^{2-} }{[HSO3]^{-} } \\6.247 = 7.00 + log\frac{x}{(1.98-x)} \\x=0.634 moles$

Volume of NaOH required is:

$\frac{0.634\ moles}{0.615 moles/L}=0.389L$

Step 3:

Total volume of NaOH required = 3.22+0.389 =3.61 L

3 0

3 years ago

You are given three liquids. You know that one of them is a suspension, one is a solution with nonelectrolytes, and the other is

Aleks [24]

Answer:

decant/ filter then decompose the electrolytes by electrolysis

Explanation:

4 0

3 years ago

Which of these represents the correctly balanced equation?

SCORPION-xisa [38]

Answer:

2HCI + Na2S ----> H2S + 2NaCl

Explanation:

For a balanced chemical equation, the number of moles of atoms on the reaction side must equal the number of moles of atoms on the product side, in accordance with the law of conservation of mass.

The correct answer is:

2HCI + Na2S ----> H2S + 2NaCl

Since it has equal number of moles of each atom on both sides of the equation: 2 atoms each of hydrogen, chlorine, and sodium on both sides of the equation as well as 1 atom of sulphur on both sides of the equation.

5 0

4 years ago