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sergejj [24]
2 years ago
7

A secondary step in the process to produce ultra-pure silicon is to combine silicon tetrachloride with magnesium. How many grams

of Si could be produced by reacting 2.00 kg of SiCl4 with excess Mg
Chemistry
1 answer:
mariarad [96]2 years ago
8 0

The mass of silicon, Si produced from the reaction is 329.41 g

<h3>Balanced equation </h3>

SiCl₄ + 2Mg —> 2MgCl₂ + Si

Molar mass of SiCl₄ = 28 + (35.5×4) = 170 g/mol

Mass of SiCl₄ from the balanced equation = 1 × 170 = 170 g

Molar mass of Si = 28 g/mol

Mass of Si from the balanced equation = 1 × 28 = 28 g

From the balanced equation above,

170 g of SiCl₄ reacted to produce 28 g of Si.

<h3>How to determine the mass of Si produced </h3>

From the balanced equation above,

170 g of SiCl₄ reacted to produce 28 g of Si.

Therefore,

2 Kg (i.e 2000 g) of SiCl₄ will react to produce = (2000 × 28) / 170 = 329.41 g of Si

Thus, 329.41 g of Si were obtained from the reaction

Learn more about stoichiometry:

brainly.com/question/14735801

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A certain first-order reaction 45% complete in 65seconds, determine the rate constant and the half life for the process ​
masha68 [24]

The rate constant : k = 9.2 x 10⁻³ s⁻¹

The half life : t1/2 = 75.3 s

<h3>Further explanation</h3>

Given

Reaction 45% complete in 65 s

Required

The rate constant and the half life

Solution

For first order ln[A]=−kt+ln[A]o

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A = 0.55

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ln A = -kt + ln Ao

ln 0.55 = -k.65 + ln 1

-0.598=-k.65

k = 9.2 x 10⁻³ s⁻¹

The half life :

t1/2 = (ln 2) / k

t1/2 = 0.693 : 9.2 x 10⁻³

t1/2 = 75.3 s

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Answer:

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