Answer:
v = 2.94 m/s
Explanation:
When the spring is compressed, its potential energy is equal to (1/2)kx^2, where k is the spring constant and x is the distance compressed. At this point there is no kinetic energy due to there being no movement, meaning the net energy in the system is (1/2)kx^2.
Once the spring leaves the system, it will be moving at a constant velocity v, if friction is ignored. At this time, its kinetic energy will be (1/2)mv^2. It won't have any spring potential energy, making the net energy (1/2)mv^2.
Because of the conservation of energy, these two values can be set equal to each other, since energy will not be gained or lost while the spring is decompressing. That means
(1/2)kx^2 = (1/2)mv^2
kx^2 = mv^2
v^2 = (kx^2)/m
v = sqrt((kx^2)/m)
v = x * sqrt(k/m)
v = 0.122 * sqrt(125/0.215) <--- units converted to m and kg
v = 2.94 m/s
<span>An example of the deregulation of a government regulated natural monopoly is where the new ;aw allows consumers to be able to choose between the electricity providers which is the first choice because a deregulation of a government regulated natural monopoly is a way of the rules of having to be remove or reduced when tackling or making use of the government regulated natural monopoly.</span>
Answer:
Explanation:
A general wave function is given by:

A: amplitude of the wave = 0.075m
k: wave number
w: angular frequency
a) You use the following expressions for the calculation of k, w, T and λ:



b) Hence, the wave function is:

c) for x=3m you have:

d) the speed of the medium:

you can see the velocity of the medium for example for x = 0:

Answer:
the tension is 18513N
Explanation:
Given that
mass = 1683kg
acceleration = 1.2m/s^2
acceleration due to gravity = 9.8m/s^2
T-mg = ma
T = ma + mg
T = m(a +g)
T = 1683 kg(1.20 m/s2 + 9.8)
T = 1683 (11)
T = 18513N
therefore, the tension is 18513N
A and D are definitely wrong because the two rocks have different masses, so it leaves us with B and C. The most logical answer to the question is
C <span>The one with greater mass takes more force to stop.
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