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zvonat [6]
3 years ago
13

As you found in Part A, your weight will be greater than normal when the elevator is moving upward with increasing speed. For wh

at other motion would your weight also be greater than your normal weight?
A) The elevator moves upward with constant velocity.
B) The elevator moves downward with constant velocity.
C) The elevator moves upward while slowing in speed.
D) The elevator moves downward while slowing in speed.
E) The elevator moves downward while increasing in speed.
Physics
1 answer:
shepuryov [24]3 years ago
4 0

Answer:

D) The elevator moves downward while slowing in speed.

Explanation:

The elevator is moving downward with decreasing speed , that means a force is acting on it in upward direction . So it has  an acceleration in upward direction . This type of movement is similar to motion with acceleration in upward direction.

In this case apparent weight will be greater.

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A child on a tricycle is moving at a speed of 1.40 m/s at the start of a 2.25 m high and 12.4 m long incline. The total mass is
goblinko [34]

Answer:

The work done by the child as the tricycle travels down the incline is 416.96 J

Explanation:

Given;

initial velocity of the child, v_i = 1.4 m/s

final velocity of the child, v_f = 6.5 m/s

initial height of the inclined plane, h = 2.25 m

length of the inclined plane, L = 12.4 m

total mass, m = 48 kg

frictional force, f_k = 41 N

The work done by the child is calculated as;

\Delta E_{mech} = W - f_{k} \Delta L\\\\W = \Delta E_{mech}  + f_{k} \Delta L\\\\W = (K.E_f - K.E_i) + (P.E_f - P.E_i) + f_{k} \Delta L\\\\W = \frac{1}{2} m(v_f^2 - v_i^2) + mg(h_f - h_i) + f_{k} \Delta L\\\\W = \frac{1}{2} \times 48(6.5^2 - 1.4^2) + 48\times 9.8(0-2.25) + (41\times 12.4)\\\\W = 966.96  \ - \ 1058.4 \ + \ 508.4\\\\W = 416.96 \ J

Therefore, the work done by the child as the tricycle travels down the incline is 416.96 J

5 0
2 years ago
Nitrogen fixation is the conversion of
Varvara68 [4.7K]

Answer:

D IS MY ANSWER N2 TO UREA HOPE ITS HELFUL

6 0
2 years ago
A certain spring stores 10.0J of potential energy when it isstretched by 2.00cm from its equilibrium position.How much potential
qaws [65]

Answer:

Answered

Explanation:

x= 0.02 m

E_p= 10.0 J

E_p= 0.5kx^2

10= 0.5k(0.02)^2

solving we get

K= 50.0 N/m

Now

E'_p= 0.5kx'^2

E'_p= 0.5×50×(0.04)^2

E'_p=40 J

b) potential energy is a scalar quantity and it only depends magnitude and not direction so it will remain same in compression and expansion both

c) 20 J = 0.5×50,000×x^2

solving

x= 0.028 m

d) k is 50.0 N/m  from above calculation

3 0
3 years ago
An air mass that is moving from the north pole toward the equator would be turned to the ? because of the spinning of the earth
siniylev [52]

Answer:

An air mass that is moving from the north pole toward the equator would be turned to the East because of the spinning of the earth on its axis

Explanation:

7 0
2 years ago
The specific heat capacity of solid copper metal is 0.385 J/gK. How many joules of heat are needed to raise the temperature of a
SSSSS [86.1K]

Answer: 26.6 J

Explanation:

The heat needed to raise the temperature of a solid body, using only  a conductive process, has been empirically showed to be equal to the following expression:

Q= c . m.  (t2 – t1)

where c= specific heat capacity (in J/gK), m= mass of the solid (in g) ,

and (t2 - t1)= difference between final and initial temperatures.

Replacing by the values, we get:

Q= 0.385 J/gK . 1,550 g. (77.5ºC – 33.0ºC)= 26.6 J

3 0
2 years ago
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