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2 years ago

14

Which is the amount of matter in an object? a. weight b.mass c.volume d.pounds

1 answer:

hodyreva [135]2 years ago

8 0

Answer:

(1.) (A.) wight

Explanation:

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Why does a balloon filled with the air from your lungs sink to the ground but a balloon filled with Helium floats ?

hoa [83]

Helium is lighter than air from the lungs.

Explanation:

A balloon filled with the air from lungs will sink to the ground but a balloon filled with Helium floats because helium is lighter than air.

Air is a mixture of many gases.

The air from the lungs is predominantly made up of carbon dioxide and water vapor.

Gram per mole of carbon dioxide is 44. Water vapor is 18.
Compared to helium which is 4, we see that the gas is lighter.
Since the gas is lighter, it will float in air.
The main component of air around us is nitrogen gas with a gram per mole of 28.
A balloon filled with more of air from the lungs weigh more than that will filled air around and even far more than helium gas.
This will cause a helium filled balloon to float.

learn more:

Density brainly.com/question/1698555

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3 years ago

A toy car having mass m = 1.10 kg collides inelastically with a toy train of mass M = 3.55 kg. Before the collision, the toy tra

kkurt [141]

Answer:

$V_{ft}= 317 cm/s$

ΔK = 2.45 J

Explanation:

a) Using the law of the conservation of the linear momentum:

$P_i = P_f$

Where:

$P_i=M_cV_{ic} + M_tV_{it}$

$P_f = M_cV_{fc} + M_tV_{ft}$

Now:

$M_cV_{ic} + M_tV_{it} = M_cV_{fc} + M_tV_{ft}$

Where $M_c$ is the mass of the car, $V_{ic}$ is the initial velocity of the car, $M_t$ is the mass of train, $V_{fc}$ is the final velocity of the car and $V_{ft}$ is the final velocity of the train.

Replacing data:

$(1.1 kg)(4.95 m/s) + (3.55 kg)(2.2 m/s) = (1.1 kg)(1.8 m/s) + (3.55 kg)V_{ft}$

Solving for $V_{ft}$ :

$V_{ft}= 3.17 m/s$

Changed to cm/s, we get:

$V_{ft}= 3.17*100 = 317 cm/s$

b) The kinetic energy K is calculated as:

K = $\frac{1}{2}MV^2$

where M is the mass and V is the velocity.

So, the initial K is:

$K_i = \frac{1}{2}M_cV_{ic}^2+\frac{1}{2}M_tV_{it}^2$

$K_i = \frac{1}{2}(1.1)(4.95)^2+\frac{1}{2}(3.55)(2.2)^2$

$K_i = 22.06 J$

And the final K is:

$K_f = \frac{1}{2}M_cV_{fc}^2+\frac{1}{2}M_tV_{ft}^2$

$K_f = \frac{1}{2}(1.1)(1.8)^2+\frac{1}{2}(3.55)(3.17)^2$

$K_f = \frac{1}{2}(1.1)(1.8)^2+\frac{1}{2}(3.55)(3.17)^2$

$K_f = 19.61 J$

Finally, the change in the total kinetic energy is:

ΔK = Kf - Ki = 22.06 - 19.61 = 2.45 J

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3 years ago

Create a list of the different methods or ways that Tonya could communicate the new policy to the staff members

Nuetrik [128]

She could text/email,report it to them personally,post up flyers,tell one person to spread it around

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3 years ago

Suppose your hair grows at the rate 1/31 in. per day. find the rate at which it grows in nanometers per second. because the dist

kati45 [8]

Hair grows at rate of 9.20nm/s.

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3 years ago

Please help<br> question #70

Keith_Richards [23]

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3 years ago