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mafiozo [28]
3 years ago
14

How do you find the change in potential energy

Physics
1 answer:
ratelena [41]3 years ago
3 0

P.E = mgh

This is the formula for potential energy.

This is where m is mass, g is the acceleration due to gravity, and h is height.

All you have to do is multiply all these numbers together.

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99 POINT QUESTION PLUS BRAINLIEST!!!
ollegr [7]
Well i cant <span>explain it as well as i would like, if i did it would make no sens, but the answer should be (C.) 60m. but i`m only 95% sure its the answer. i hope this helps!</span>
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2 years ago
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Ne4ueva [31]

Answer:

d solid

Explanation: brainlist plz

solids have a definite shape and volume

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2 years ago
A planet has two
lozanna [386]
Kepler's third law hypothesizes that for all the small bodies in orbit around the
same central body, the ratio of (orbital period squared) / (orbital radius cubed)
is the same number.

<u>Moon #1:</u>  (1.262 days)² / (2.346 x 10^4 km)³

<u>Moon #2:</u>  (orbital period)² / (9.378 x 10^3 km)³

If Kepler knew what he was talking about ... and Newton showed that he did ...
then these two fractions are equal, and may be written as a proportion.

Cross multiply the proportion:

(orbital period)² x (2.346 x 10^4)³ = (1.262 days)² x (9.378 x 10^3)³

Divide each side by (2.346 x 10^4)³:

(Orbital period)² = (1.262 days)² x (9.378 x 10^3 km)³ / (2.346 x 10^4 km)³

               =  0.1017 day²

Orbital period = <u>0.319 Earth day</u> = about 7.6 hours.
7 0
3 years ago
A ball, with a mass of 5.9kg, is thrown directly upwards. It reaches a maximum height of 10m from the point at which it was rele
katrin2010 [14]

Answer:

14 m/s

Explanation:

We can solve the problem by using the law of conservation of energy.

At the beginning, when the ball is thrown from the ground, it has only kinetic energy, which is given by

K=\frac{1}{2}mv^2

where m = 5.9 kg is the mass of the ball and v is its initial speed.

As the ball goes up, its speed decreases, so its kinetic energy decreases and converts into gravitational potential energy. When the ball reaches its maximum height, the speed has become zero, and all the kinetic energy has been converted into gravitational potential energy, given by:

U=mgh

where g = 9.8 m/s^2 is the gravitational acceleration and h = 10 m is the maximum height reached by the ball.

Since we can ignore air resistance, energy must be conserved, so the initial kinetic energy must be equal to the final potential energy of the ball, so we can write:

K=U\\\frac{1}{2}mv^2=mgh

And we can solve the equation to find v, the initial speed of the ball:

v=\sqrt{2gh}=\sqrt{2(9.8 m/s^2)(10 m)}=14 m/s


8 0
2 years ago
A new piece of exercise equipment has been added to your gym, and you try it out. To use this machine, you lie horizontal on a m
Shalnov [3]

Answer:

500 N

Explanation:

Since the work done on the spring W = Fx where F = force applied and x = compression length = 0.170 m (since the spring will be compressed its full length when the force is applied)

Since W = 85.0 J and we need to find F,

F = W/x

= 85.0 J/0.170 m

= 500 N

So, the  magnitude of force must you apply to hold the platform stationary at the final distance given above is 500 N.

6 0
3 years ago
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