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Katena32 [7]
2 years ago
6

If a liquid substance is transferred to a different container, what can be predicted about the volume of the liquid in the new c

ontainer?
Chemistry
1 answer:
taurus [48]2 years ago
8 0

The same

Explanation:

If a liquid substance is transferred to a different container, the volume of the liquid in the new container will remain the same.

The volumes of liquids are fixed and does not change. Wherever they are contained, just like solids, they maintain their constant space.

  • Volume is the amount of space occupied by a body.
  • Gases do not have fixed volume as they fill their containers and they take up the shape.
  • Solids and liquids have a fixed volume.
  • They do not change their volume.

learn more:

State of matter brainly.com/question/10972073

#learnwithBrainly

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Identify which subatomic particles match each of these descriptions. One of the descriptions describes two particles. Make sure
Advocard [28]

Explanation:

protons have a relative charge of +1, they are located in the nucleus and the carry a positive charge

the electrons are negatively charged and have a charge of -1 . They are found orbiting on the shells .the electrons have a negligible mass of 1 / 1840

the neutrons have no charge they are located in the nucleus of an atom .

5 0
2 years ago
A doctor's Order is 0.125 g of ampicillin. The liquid suspension on hand contains 250 mg/s. How many milliliters (mL) of the sus
Molodets [167]

Answer:

c) 2.5 mL

Explanation:

Solution

Doctors order = 0.125g

and

The liquid suspension concentration = 250 mg/5ml

= 0.250g/5ml

Or 0.05g/ml

Amount of ml of suspension required = 0.125g/(0.05g/ml) = 2.5ml

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3 years ago
A solid calcium metal reacts with molecular oxygen.<br> WORD EQUATION =<br> CHEMICAL EQUATION =
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5 0
3 years ago
Calculate the OH− concentration after 53 mL of the 0.100 M KOH has been added to 25.0 mL of 0.200 M HBr. Assume additive vol- um
Andre45 [30]

Answer:

\large \boxed{\text{0.0038 mol/L}}

Explanation:

1. Calculate the initial moles of acid and base

\text{moles of acid} = \text{0.0250 L} \times \dfrac{\text{0.200 mol}}{\text{1 L}} = \text{0.005 00 mol}\\\\\text{moles of base} = \text{0.053 L} \times \dfrac{\text{0.100 mol}}{\text{1 L}} = \text{0.0053 mol}

2. Calculate the moles remaining after the reaction

                   OH⁻     +     H₃O⁺ ⟶ 2H₂O

I/mol:      0.0053       0.005 00

C/mol:    -0.00500   -0.005 00

E/mol:      0.0003              0

We have an excess of 0.0003 mol of base.

3. Calculate the concentration of OH⁻

Total volume = 53 mL + 25.0 mL = 78 mL = 0.078 L

\text{[OH}^{-}] = \dfrac{\text{0.0003 mol}}{\text{0.078 L}} = \textbf{0.0038 mol/L}\\\\\text{The final concentration of OH$^{-}$ is $\large \boxed{\textbf{0.0038 mol/L}}$}

8 0
2 years ago
Cree que podríamos vivir sin leyes
astraxan [27]

Answer:

nop

Explanation:

porqUE todo sería un desastre

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